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Law Incorporation [45]
3 years ago
10

Im not sure what to do here or how to start for AP calculus

Mathematics
2 answers:
Alborosie3 years ago
6 0
What’s the question ?
alexdok [17]3 years ago
4 0
No clue sorry but maybe this helps: http://tutorial.math.lamar.edu/Classes/CalcI/OneSidedLimits.aspx
You might be interested in
Find an example for each of vectors x, y ∈ V in R.
rjkz [21]

(a) Both conditions are satisfied with <em>x</em> = (1, 0) for \mathbb R^2 and <em>x</em> = (1, 0, 0) for \mathbb R^3:

||(1, 0)|| = √(1² + 0²) = 1

max{1, 0} = 1

||(1, 0, 0)|| = √(1² + 0² + 0²) = 1

max{1, 0, 0} = 1

(b) This is the well-known triangle inequality. Equality holds if one of <em>x</em> or <em>y</em> is the zero vector, or if <em>x</em> = <em>y</em>. For example, in \mathbb R^2, take <em>x</em> = (0, 0) and <em>y</em> = (1, 1). Then

||<em>x</em> + <em>y</em>|| = ||(0, 0) + (1, 1)|| = ||(1, 1)|| = √(1² + 1²) = √2

||<em>x</em>|| + ||<em>y</em>|| = ||(0, 0)|| + ||(1, 1)|| = √(0² + 0²) + √(1² + 1²) = √2

The left side is strictly smaller if both vectors are non-zero and not equal. For example, if <em>x</em> = (1, 0) and <em>y</em> = (0, 1), then

||<em>x</em> + <em>y</em>|| = ||(1, 0) + (0, 1)|| = ||(1, 1)|| = √(1² + 1²) = √2

||<em>x</em>|| + ||<em>y</em>|| = ||(1, 0)|| + ||(0, 1)|| = √(1² + 0²) + √(0² + 1²) = 2

and of course √2 < 2.

Similarly, in \mathbb R^3 you can use <em>x</em> = (0, 0, 0) and <em>y</em> = (1, 1, 1) for the equality, and <em>x</em> = (1, 0, 0) and <em>y</em> = (0, 1, 0) for the inequality.

(c) Recall the dot product identity,

<em>x</em> • <em>y</em> = ||<em>x</em>|| ||<em>y</em>|| cos(<em>θ</em>),

where <em>θ</em> is the angle between the vectors <em>x</em> and <em>y</em>. Both sides are scalar, so taking the norm gives

||<em>x</em> • <em>y</em>|| = ||(||<em>x</em>|| ||<em>y</em>|| cos(<em>θ</em>)|| = ||<em>x</em>|| ||<em>y</em>|| |cos(<em>θ</em>)|

Suppose <em>x</em> = (0, 0) and <em>y</em> = (1, 1). Then

||<em>x</em> • <em>y</em>|| = |(0, 0) • (1, 1)| = 0

||<em>x</em>|| • ||<em>y</em>|| = ||(0, 0)|| • ||(1, 1)|| = 0 • √2 = 0

For the inequality, recall that cos(<em>θ</em>) is bounded between -1 and 1, so 0 ≤ |cos(<em>θ</em>)| ≤ 1, with |cos(<em>θ</em>)| = 0 if <em>x</em> and <em>y</em> are perpendicular to one another, and |cos(<em>θ</em>)| = 1 if <em>x</em> and <em>y</em> are (anti-)parallel. You get everything in between for any acute angle <em>θ</em>. So take <em>x</em> = (1, 0) and <em>y</em> = (1, 1). Then

||<em>x</em> • <em>y</em>|| = |(1, 0) • (1, 1)| = |1| = 1

||<em>x</em>|| • ||<em>y</em>|| = ||(1, 0)|| • ||(1, 1)|| = 1 • √2 = √2

In \mathbb R^3, you can use the vectors <em>x</em> = (1, 0, 0) and <em>y</em> = (1, 1, 1).

8 0
3 years ago
Samantha received an allowance of $3 every week. By babysitting, she earned $30 every week. How much did Samantha have in four w
kvasek [131]
Okay, so there are 4 weeks in a month. 30x4 is 120,and 3x4 is 12. Add the 2 together and you have 132$
6 0
3 years ago
you and a friend go out to dinner. The cost of the meal is $45.22. The sales tax is 5% and deliver 16% tip. what is the total co
kumpel [21]

Answer: $57.72

Step-by-step explanation:

4 0
3 years ago
Can someone clearly explain and workout Q19? Much appreciated
Anna007 [38]
The x coefficient is 2
Take half of 2 to get 2/2 = 1
Square 1 to get 1^2 = 1

Add and subtract 1 to the expression. This is the same as adding 0. 

x^2 + 2x + 2
x^2 + 2x + 2 + 0
x^2 + 2x + 2 + (1-1)
(x^2 + 2x + 1) + 2 - 1
(x+1)^2 + 1

Answer: (x+1)^2 + 1

 
5 0
3 years ago
There are between 50 &amp; 60 eggs in a basket. When roza counts by 3's there are 2 leftover and when she counts by 5's there ar
avanturin [10]

There are 59 eggs in the basket

Step-by-step explanation:

There are between 50 & 60 eggs in a basket

  • When Roza counts by 3's there are 2 leftover
  • When she counts by 5's there are 4 leftover

We need to find how many eggs in the basket

∵ When Roza counts by 3's there are 2 leftover

∵ When she counts by 5's there are 4 leftover

- That means the number of eggs when divided by 3 give

  remainder 2 and when divided by 5 give remainder 4

- To find the number look for the numbers that divisible by 5 and

  add 4 to them and then check the remainder when they divided

  by 3

∵ Between 50 and 60 there is only one number divisible by 5

  is 55 (not including 50 or 60)

∵ 55 + 4 = 59

∴ 59 gives remainder 4 when divided by 5

Let us check them with 3

∵ 59 - 2 = 57

∵ 57 is divisible by 3 ⇒ (57 ÷ 3 = 19)

∴ 59 when divide by 3 gives remainder 2

∴ 59 gives remainder 4 when divided by 5 and remainder 2 when

  divided by 3

∴ The number of eggs in the basket is 59

There are 59 eggs in the basket

Learn more:

You can learn more about the word problems in brainly.com/question/10557938

#LearnwithBrainly

6 0
3 years ago
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