<span>First, the child's weight must be converted from pounds to kilograms.
1 lb is equal to 0.453592 kg, so a 13 lb child weighs:
13 lb * 0.453592 kg/lb = 5.896696 kg
Next, use the child's converted weight to determine the mg dosage. The recommended dose is 15 mg per kg, so the recommended dose is:
15 mg/kg * 5.896696 kg = 88.45044 mg
Finally, determine how many mL are needed to provide the calculated mg dosage. One unit of the suspension is 80 mg/0.80 mL. In order to provide 88.45044 mg, you will need
88.45044 mg / 80 mg = 1.1056305 units of the suspension.
Multiplying this by the 0.80 mL portion of the unit of the suspension, you get the final mL dosage:
0.80 mL * 1.1056305 = 0.8845044 mL
A 13 lb child should receive 0.8845044 mL of the 80mg/.8mL suspension.</span>
Answer: I think its c or d
Explanation:
Sodium carbonate contains 3 elements: Na, C, and O. Step 2: Determine how many atoms of each element are in the formula. Na, Co, is made up of Na, C, and O3, so Na.co, has 2 atoms of sodium (Na) 1 atom of carbon (C) and 3 atoms of oxygen (O).
Water stores energy more efficiently than air under equal conditions.
It requires more energy to heat water than it does to heat air because water has a significantly larger heat capacity and specific heat than air. Compared to air, which has a specific heat of 1.005 J/g degreesC, water has a specific heat of 4.186 J/g degreesC.
Specific heat:
The amount of heat required to raise the temperature per unit mass is known as specific heat capacity. The heat in Joules required to increase the temperature of 1 gram of sample by 1 Kelvin or degree Celsius is often stated. Water is an excellent temperature regulator since it has a very high specific heat capacity.
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5.367 ml of the concentrated acid must be added to obtain a total volume of 100 ml of the dilute solution.
Dilution is defined as the process in which the concentration of a sample is decreased by adding more solvent. The dilution formula is given below.
C₁V₁ = C₂V₂
where C₁ = initial concentration of sample = 3.00 m
V₁ = initial volume of sample
C₂ = final concentration after dilution = 0.161 m
V₂ = total final volume after dilution = 100 ml
Plug in the values to the formula and solve for the volume of the concentrated acid that must be added.
C₁V₁ = C₂V₂
3.00 m (V₁) = 0.161 m (100 ml)
V₁ = 5.367 ml
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