The mass of calcium hydroxide that is formed when 10.0 g of CaO reacts with 10.0 g of water is 13.024 grams
calculation
from the equation
CaO + H2O → Ca(OH)2,
1 moles of CaO reacted with 1 moles of H2O to form 1 moles of Ca(OH)2
find the moles of each reactant
moles=mass/molar mass
moles of CaO= 10 g/56 g/mol=0.179 moles
moles of H2O = 10 g/18 g/mol 0.556 moles
CaO is the limiting reagent therefore by use of mole ratio of CaO:Ca(OH)2 which is 1:1 moles of Ca(OH)2 is = 0.179 moles
mass= moles x molar mass
= 0.176 moles x 74 g/mol = 13.024 grams
Answer:
Remove exess water
Explanation:
The reaction involved is an esterification reaction. Esterification is a reaction in which alcohol and carboxylic acid reacts to yield an ester and water. It is analogous to the inorganic neutralization reaction.
According to Le Chatelier's principle , one method of driving the equilibrium towards the forward reaction is by removal of one of the products. In this case, if water is removed, the forward reaction is favoured.
Answer:
because they change
Explanation:
It was based on theories and discoveries
Answer:
42686.04375
Explanation:
847.3219*34.6=2317.33774 multiply this by the next number 1.4560 to get 42686.04375