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Maurinko [17]
3 years ago
12

Fe(s) + 2HCl(aq) --> FeCl2(aq) + H2(g)

Chemistry
1 answer:
soldier1979 [14.2K]3 years ago
8 0

Answer:

In the option(A) moles of HCl left are 0.100 moles which is wrong, making the option incorrect.

Explanation:

Fe(s) + 2HCl(aq)\rightarrow  FeCl_2(aq) + H_2(g)


Moles of HCl = n

Molarity of HCl = 1.0M

Volume of HCl solution = 30.0 mL = 0.030 L (1 mL = 0.001L)

Moles=Molarity\times Volume (L)

n=1.0M\times 0.030 L=0.030 mol

Moles of Fe = \frac{0.56 g}{56 g/mol}=0.01 mol

According to recation , 1mol of Fe reacts with 2 mol HCl. Then 0.01 mole of Fe will recat with :

\frac{2}{1}\times 0.01 mol= 0.02 mol of HCl

This means that HCl uis in excess , hence excessive reagent.

Moles of HCl left unreacted :

= 0.030 mol - 0.020 mol = 0.010 mol

But in the option moles of HCl left are 0.100 moles which is wrong, making the option incorrect.

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