The ideal gas law may be written as

where
p = pressure
ρ =density
T = temperature
M = molar mass
R = 8.314 J/(mol-K)
For the given problem,
ρ = 0.09 g/L = 0.09 kg/m³
T = 26°C = 26+273 K = 299 K
M = 1.008 g/mol = 1.008 x 10⁻³ kg/mol
Therefore

Note that 1 atm = 101325 Pa
Therefore
p = 2.2195 x 10⁵ Pa
= 221.95 kPa
= (2.295 x 10⁵)/101325 atm
= 2.19 atm
Answer:
2.2195 x 10⁵ Pa (or 221.95 kPa or 2.19 atm)
Answer:
4HCl(g) + O₂(g) → 2Cl₂(g) + 2H₂O(g)
Explanation:
In order to find the equation we should state:
The reactants → Hydrogen chloride (HCl) and oxygen (O₂)
The products → Chlorine gas (Cl₂) and water gas (H₂O)
The balanced equation is:
4HCl + O₂ → 2Cl₂ + 2H₂O
It is a redox reaction, where the oxygen reduces to make water, and the chloride is oxidized to produce elemental chlorine.
I because it is an acid, it should be soluble in hexane
Answer:
C
Explanation:
C because there is more in it than the rest of the idems
Answer:
2) Add a solution of NaBr
Explanation:
Lead (II) bromide is an inorganic powdery substance that has a solubility in water of 0.973 g/100 mL at 20°C. It is insoluble in alcohol but is soluble in alkali, ammonia, NaBr, and KBr
PbBr₂ is slightly soluble in ammonia, and it reacts with NaOH to produce Pb(OH)₂ and NaBr
Therefore, the best solution for dissolving PbBr₂(s) is NaBr