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lisov135 [29]
3 years ago
11

To get admitted to top universities, the applicant's SAT (Scholastic Aptitude Test) score must be on a very high side. In terms

of concepts learned in MAT201, this means that: Question 9 options: A) The applicant's SAT z-score has to be positive and large. B) The applicant's SAT z-score has to be negative. C) The applicant's SAT z-score has to be close to zero D) The applicant's SAT z-score has to be close to one.
Mathematics
1 answer:
Gekata [30.6K]3 years ago
6 0

Answer:

A) The applicant's SAT z-score has to be positive and large.

Step-by-step explanation:

The zscore measures how much above or below the mean a value is in a normally distributed sample. The value can be a grade, for example.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}.

When the zscore of X is negative and large, this means that the grade is on the very low side(very below the mean).

When the zscore of X is negative and small, this means that the grade is on the low side(a bit below the mean).

When the zscore of X is close to 0, the grade is close to the mean.

When the zscore of X is positive and small, this means that the grade is on the high side(a bit above the mean).

When the zscore of X is positive and large(Z > 1), this means that the test score is on a very high side.

The problem states that:

To get admitted to top universities, the applicant's SAT (Scholastic Aptitude Test) score must be on a very high side. So, the correct answer is:

A) The applicant's SAT z-score has to be positive and large.

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(219,379.01 - x) / x = .3321
Ivahew [28]

Answer:x = 164686.592598

Step-by-step explanation:

219379.01−x/x = 0.3321

−x+219379.01/x = 0.3321

Step 1: Multiply both sides by x.

−x+219379.01≈0.3321x

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6 0
3 years ago
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Vesnalui [34]

Answer:

Option B. x=-\frac{9}{28}(+/-)\frac{\sqrt{479}}{28}i

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

14x^{2}+9x+10=0

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substitute in the formula

x=\frac{-9(+/-)\sqrt{9^{2}-4(14)(10)}} {2(14)}

x=\frac{-9(+/-)\sqrt{-479}} {28}

Remember that

i=\sqrt{-1}

substitute

x=\frac{-9(+/-)\sqrt{479}i} {28}  

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✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

                  Hello!

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

❖ The 3 remains the same when 9,321 is rounded because if you look to the right of the number in the hundreds place, you see 2. 5 and above, give it a shove (round up). 4 and below, leave it alone (round down). Since 2 is below 5, we leave it alone. So 9,321 is rounded to 9,300.

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

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