-6 is an integer, but not a whole number.
Answer:
270
Step-by-step explanation:
three are 140 boys for every girl 130 girls 270
The sample space of an event is the list of possible elements of the event.
The set elements are:
- Ac = {x : 0, 5 ≤ x ≤ 10}
- A n B = {x : 3 ≤ x ≤ 4}
- A ∪ B = {x : 0 < x ≤ 7}
- A∩Bc = {x : 1 ≤ x ≤ 2}
- A^c ∪ B = {x : 0, 3 ≤ x ≤ 10}
<h3>How to determine the intervals of the subsets</h3>
The given parameters are:
S = {x : 0 ≤ x ≤ 10}
A = {x : 0 < x < 5}
B = {x : 3 ≤ x ≤ 7}
<u>(a) Ac </u>
This represents the list of elements in the universal set not in set A.
So, we have:
Ac = {x : 0, 5 ≤ x ≤ 10}
<u>(b) A ∩ B </u>
This represents the list of common elements in sets A and set B.
So, we have:
A n B = {x : 3 ≤ x ≤ 4}
<u>(c) A ∪ B </u>
This represents the list of all elements in sets A and set B, without repetition.
So, we have:
A ∪ B = {x : 0 < x ≤ 7}
<u>d) A∩Bc </u>
Given that:
B = {x : 3 ≤ x ≤ 7}
So, we start by calculating B^c i.e. the list of elements in the universal set not in set B.
So, we have:
Bc = {x : 1, 2, 8 ≤ x ≤ 10}
A∩Bc would then represent the list of common elements in sets A and set Bc
So, we have:
A∩Bc = {x : 1 ≤ x ≤ 2}
<u>(e) A^c ∪ B</u>
In (a), we have:
Ac = {x : 0, 5 ≤ x ≤ 10}
Given that:
B = {x : 3 ≤ x ≤ 7}
A^c ∪ B would then represent the list of all elements in sets Ac and set B
So, we have:
A^c ∪ B = {x : 0, 3 ≤ x ≤ 10}
Read more about sets are:
brainly.com/question/2193811
Answer:
a reflection across line bc
Step-by-step explanation:
maybe, I think so
The weighted average unit cost after the October 22 purchase is $13.70.
<h3>What is the weighted average unit cost?
</h3>
The weighted average unit cost determines the weighted average cost of all the purchased inventory.
[(300 x 12) + (390 x 15) ] / (300 + 390)
(3600 + 5850) / 690 = $13.70
To learn more about the weighted average method, please check: brainly.com/question/28018617
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