Answer:
2 vertical asymptotes occurring at x = 5 and x = -1
Step-by-step explanation:
given
![f(x) = \frac{14}{(x-5)(x+1)}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B14%7D%7B%28x-5%29%28x%2B1%29%7D)
recall that asymptotic occur at the locations that will make the equation undefined. In this case, the asymptote will occur at x-locations which will cause the denominator to become zero (and hence undefined)
Equating the denominator to zero,
(x-5)(x+1) = 0
(x-5) =0
x = 5 (first asymptote)
or (x+1) = 0
x = -1 (2nd asymptote)
Answer:
B
Step-by-step explanation:
10×1=10
0+10=10
Hence they're equal
Answer:
7
Step-by-step explanation:
There is a point of inflection at each point where the graph crosses the line y=2. There are 7 points of inflection shown.
__
A point of inflection is where the graph changes from being concave downward to concave upward, or vice versa. For a sine function, that is everywhere the function crosses its midline.
Answer:
<h2>
W = 1/6</h2>
Step-by-step explanation:
Hope this helps
<h2><em>
:)</em></h2>
Answer:
indeed it does
Step-by-step explanation:
wheres the diagram exactly?