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The easiest way to solve this is to divide the shape into 2 rectangles.
The first rectangle being the big one on the left with the 12 and 6
and the second one being the little one on the right, next to it with the 5
So 12 x 6 = 72 (dont pay attention to the 7, 5, or 10, because all we need is 1 length and 1 width)
And for the smaller one it is a little bit trickier.
So on the bottom we see that is says 10ft, but we cant use that because what we really need is the measurement between the 5 and 7 on the top of the little rectangle
At the top we see that it says 6ft
We can do 10-6 to find the missing measurement.
Because the length of the whole like is 10, and the length of one of the little lines is 6, so the length of 6 + some number =10
So 10-6 = 4
Which means the number we need is 4
So now we have 5 x 4 = 20
72 + 20 = 92
Answer: 92
I also attatched an image, I hope this helps! Ask me if you have any other questions about this problem!
The first rectangle being the big one on the left with the 12 and 6
and the second one being the little one on the right, next to it with the 5
So 12 x 6 = 72 (dont pay attention to the 7, 5, or 10, because all we need is 1 length and 1 width)
And for the smaller one it is a little bit trickier.
So on the bottom we see that is says 10ft, but we cant use that because what we really need is the measurement between the 5 and 7 on the top of the little rectangle
At the top we see that it says 6ft
We can do 10-6 to find the missing measurement.
Because the length of the whole like is 10, and the length of one of the little lines is 6, so the length of 6 + some number =10
So 10-6 = 4
Which means the number we need is 4
So now we have 5 x 4 = 20
72 + 20 = 92
Answer: 92
I also attatched an image, I hope this helps! Ask me if you have any other questions about this problem!
Refer to the diagram shown below.
The volume of the container is 10 m³, therefore
x*2x*h = 10
2x²h = 10
h = 5/x² (1)
The base area is 2x² m².
The cost is $10 per m², therefore the cost of the base is
(2x²)*($10) = 20x²
The area of the sides is
2hx + 2(2xh) = 6hx = 6x*(5/x²) = 30/x m²
The cost is $6 per m², therefore the cost of the sides is
(30/x)*($6) = 180/x
The total cost is
C = 20x² + 180/x
The minimum cost is determined by C' = 0.
That is,
40x - 180/x² = 0
x³ = 180/40 = 4.5
x = 1.651
The second derivative of C is
C'' = 40 + 360/x³
C''(1.651) = 120 >0, so x = 1.651 m yields the minimum cost.
The total cost is
C = 20(1.651)² + 180/1.651 = $163.54
Answer: $163.54
The volume of the container is 10 m³, therefore
x*2x*h = 10
2x²h = 10
h = 5/x² (1)
The base area is 2x² m².
The cost is $10 per m², therefore the cost of the base is
(2x²)*($10) = 20x²
The area of the sides is
2hx + 2(2xh) = 6hx = 6x*(5/x²) = 30/x m²
The cost is $6 per m², therefore the cost of the sides is
(30/x)*($6) = 180/x
The total cost is
C = 20x² + 180/x
The minimum cost is determined by C' = 0.
That is,
40x - 180/x² = 0
x³ = 180/40 = 4.5
x = 1.651
The second derivative of C is
C'' = 40 + 360/x³
C''(1.651) = 120 >0, so x = 1.651 m yields the minimum cost.
The total cost is
C = 20(1.651)² + 180/1.651 = $163.54
Answer: $163.54