Answer:
- 50 ft by 75 ft
- 3750 square feet
Step-by-step explanation:
Let x represent the length of the side not parallel to the partition. Then the length of the side parallel to the partition is ...
y = (300 -2x)/3
And the enclosed area is ...
A = xy = x(300 -2x)/3 = (2/3)(x)(150 -x)
This is the equation of a parabola with x-intercepts at x=0 and x=150. The line of symmetry, hence the vertex, is located halfway between these values, at x=75.
The maximum area is enclosed when the dimensions are ...
50 ft by 75 ft
That maximum area is 3750 square feet.
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<em>Comment on the solution</em>
The generic solution to problems of this sort is that half the fence (cost) is used in each of the orthogonal directions. Here, half the fence is 150 ft, so the long side measures 150'/2 = 75', and the short side measures 150'/3 = 50'. This remains true regardless of the number of partitions, and regardless if part or all of one side is missing (e.g. bounded by a barn or river).
Answer:
B is the answer for sure, because there are two outliers, there is a visible line, and they are not at all clustered around a single point
Answer:
The answer to your question is r = 4 in
Step-by-step explanation:
Data
Volume = 4000 π in³
height = 250 in
radius = ?
Process
1.- Look the formula to calculate the volume of a cylinder
Volume = πr²h
2.- Solve for r²
r² = Volume / πh
3.- Substitution
r² = 4000π / π(250)
4.- Simplification
r² = 16
r = √16
5.- Result
r = 4 in
Answer:
Step-by-step explanation:
Given
--- lower diameter
--- upper diameter
Solving (a): The curved surface area
This is calculated as:
Where
--- lower radius
--- upper radius
And
---- l represents the slant height of the frustrum
So, we have:
Solving (b): The volume
This is calculated as:
This gives:
Rational number, in arithmetic, a number that can be represented as the quotient p/q of two integers such that q ≠ 0. In addition to all the fractions, the set of rational numbers includes all the integers, each of which can be written as a quotient with the integer as the numerator and 1 as the denominator.
