If x is a real number such that x3 + 4x = 0 then x is 0”.Let q: x is a real number such that x3 + 4x = 0 r: x is 0.i To show that statement p is true we assume that q is true and then show that r is true.Therefore let statement q be true.∴ x2 + 4x = 0 x x2 + 4 = 0⇒ x = 0 or x2+ 4 = 0However since x is real it is 0.Thus statement r is true.Therefore the given statement is true.ii To show statement p to be true by contradiction we assume that p is not true.Let x be a real number such that x3 + 4x = 0 and let x is not 0.Therefore x3 + 4x = 0 x x2+ 4 = 0 x = 0 or x2 + 4 = 0 x = 0 orx2 = – 4However x is real. Therefore x = 0 which is a contradiction since we have assumed that x is not 0.Thus the given statement p is true.iii To prove statement p to be true by contrapositive method we assume that r is false and prove that q must be false.Here r is false implies that it is required to consider the negation of statement r.This obtains the following statement.∼r: x is not 0.It can be seen that x2 + 4 will always be positive.x ≠ 0 implies that the product of any positive real number with x is not zero.Let us consider the product of x with x2 + 4.∴ x x2 + 4 ≠ 0⇒ x3 + 4x ≠ 0This shows that statement q is not true.Thus it has been proved that∼r ⇒∼qTherefore the given statement p is true.
Answer:
73 units
Step-by-step explanation:
I'm pretty sure
Answer:
(2x+3)(x+1)
Step-by-step explanation:
6x² + 2x + 9x +3
(6x² + 2x) + (9x +3)
2x (x+1) + 3 (x+1)
(2x+3)(x+1)
The factored form of 2/3 times + 4 is as follows:
Since 2 is the greatest common factor among the two terms, therefore:
(2/3x + 4) = 2*(1/3 +2)
The factored form for the expression would be 2*(1/3 +2). I hope my answer has come to your help. God bless and have a nice day ahead!
Ax-6=dx -8
ax-dx =-2
X(a-d)=-2
x=-2/(a-d)