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Charra [1.4K]
3 years ago
15

A proportion often shows the relationship between:

Mathematics
1 answer:
tankabanditka [31]3 years ago
8 0

Answer:

It compares two numbers that can represent many of things. For example, people, food & items.

Step-by-step explanation:

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I need help!
Naddik [55]

Answer:  Estimate: 36  ? units ? miles per hour ? feet per second?

Exact: 35.32142857  but if you are supposed to use significant digits, 35.32 is probably good.

Step-by-step explanation: For the estimate, round off the fractions to whole numbers, so multiply 6 x 6 to get 36

For exact I converted the mixed numbers to improper fractions, 5 3/4 = 23/4  and 6 1/7 = 43/7. Then multiplied the numerators 23 x 43= 989.  And denominators, 4x7=28.  

Divide numerator by denominator  989/28= 35.321428571

7 0
3 years ago
Help please this is hard i'll mark you the brainlyest!
melomori [17]

Answer:

c

Step-by-step explanation:

c, because if you're doing a percentage of kids who bring lunches you need to do every grade level and every student to get a proper percentage

3 0
3 years ago
Add [ -6 -2 2] + [-3 2 1]
Troyanec [42]
-6 (negative six) is the answer
8 0
3 years ago
Read 2 more answers
Help me please! Will give 20 Brainly points!
Vitek1552 [10]
The first one would be 5 and the second is 3 thanks and mark as brainiliest
3 0
3 years ago
A survey of 35 people was conducted to compare their self-reported height to their actual height. The difference between reporte
monitta

Answer:

The test statistic is t = 3.36.

Step-by-step explanation:

You're testing the claim that the mean difference is greater than 0.7.

At the null hypothesis, we test if it is 0.7 or less, that is:

H_0: \mu \leq 0.7

At the alternate hypothesis, we test if it is greater than 0.7, that is:

H_1: \mu > 0.7

The test statistic is:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

0.7 is tested at the null hypothesis:

This means that \mu = 0.7

Survey of 35 people. From the sample, the mean difference was 0.95, with a standard deviation of 0.44.

This means that n = 35, X = 0.95, s = 0.44

Calculate the test statistic

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{0.95 - 0.7}{\frac{0.44}{\sqrt{35}}}

t = 3.36

The test statistic is t = 3.36.

7 0
3 years ago
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