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meriva
4 years ago
5

5/x^2-43/x=18? What is the solution to this problem

Mathematics
1 answer:
Ray Of Light [21]4 years ago
7 0
Let's solve your equation step-by-step.
5
x
2
−
43
x
=
18
5
x
x
+
−
43
x
=
18
Multiply all terms by xx and cancel:
5
+
−
43
x
=
18
x
x
−
43
x
+
5
=
18
x
2
(Simplify both sides of the equation)
−
43
x
+
5
−
18
x
2
=
18
x
2
−
18
x
2
(Subtract 18x^2 from both sides)
−
18
x
2
−
43
x
+
5
=
0
(
−
9
x
+
1
)
(
2
x
+
5
)
=
0
(Factor left side of equation)
−
9
x
+
1
=
0
or
2
x
+
5
=
0
(Set factors equal to 0)
x
=
1
9
or
x
=
−
5
2
Check answers. (Plug them in to make sure they work.)
x
=
1
9
(Works in original equation)
x
=
−
5
2
(Works in original equation)
Answer:
x
=
1
9
or
x
=
−
5
2

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A clothing company has 4 different kinds of sweatshirts. Each year, the company makes 60,000 of each kind of sweatshirt. How man
Anna007 [38]

Answer:

Step-by-step explanation:

Given that,

The company makes 4 different sweat shirts

Each year they make 60,000 of each kind.

So, if they will make 60,000 sweat shirt for each brand and the company design 4 different brand.

So, number of brand is 4

n = 4.

Then,

1 brand = 60,000

Therefore, 4 brand = 60,000 × 4

4brand = 240,000 sweat shirts.

So, in a year the company will make 240,000 sweat shirts.

4 0
3 years ago
In the spinner below, what is true about the probability of landing on 3 and the probability of landing on 4?
Karo-lina-s [1.5K]

Answer:

C.The probabilities are equal.  

The above statement is the only TRUE statement.

Step-by-step explanation:

Here, the given number of total possibilities are { 0,1,2,3,4,5,6,7,8,9}

So, number of total outcomes = 10

Let E : Event of spinner landing on 3

and E' : Even of spinner landing on 4

{Probability of Event E}  =  \frac{\textrm{Total number of favorable outcomes}}{\textrm{Toatl outcomes}}

\implies P(E) = \frac{1}{10}

⇒ P( landing on 3 ) = 1/10

and  P(E') = \frac{1}{10}

P( landing on 4 ) = 1/10

Now, the given statements are

A.The probability of landing on 3 is less than  probability of landing on 4.

FALSE, as both the probabilities are equal to 1/10.

B.The probability of landing on 3 is greater than probability of landing on 4.

FALSE, as both have same probabilities.

C.The probabilities are equal.

TRUE, both have same probability = 1/10

D.The probabilities cannot be predicted

FALSE, the probability are predictable.

3 0
3 years ago
Read 2 more answers
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