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N76 [4]
3 years ago
12

i don't get it how the question says select all that apply and only give us one answer don't you think its common sense that the

re is more than one answer ???
Chemistry
1 answer:
Klio2033 [76]3 years ago
8 0
You should probably ask your teacher the next day, there may be a mistake.
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If gas pressure is held constant and the temperature is decreased, gas volume will _____
saw5 [17]

Answer:

Increase

Explanation:

If temperature is held constant, the equation is reduced to Boyle's law. Therefore, if you decrease the pressure of a fixed amount of gas, its volume will increase.

5 0
4 years ago
This is a mixture in which two or more substances are so completely blended that is looks like one substance.
Olin [163]
Solution. because the substances can't go back to their original form. like kool aid, when its mixed you cant separate the powder and the water again.
6 0
4 years ago
How many megagrams are in 90.532 g?
Fed [463]
9.0532e-5 should be correct! hope this helps
7 0
3 years ago
The pH scale for acids and bases ranges from _____.
Elza [17]
The pH scale for acids and bases ranges from 1 - 14. The answer is letter C. The rest of the choices do not answered the question above. There are quite a few relationships between [H+] and [OH−] ions. And because there is a large range of number between 10 to 10-15 M, the pH is used. pH = -log[H+] and pOH = -log[OH−]. In aqueous solutions, [H+ ][OH- ] = 10-14. From here we can derive the values of each concentration.

 

 -log[H+ ] + -log[OH- ] = -log[10-14]

pH + pOH = 14

So pH = 14 – pOH and pOH = 14 – pH 

8 0
3 years ago
Read 2 more answers
150.0 grams of AsF3 were reacted with 180.0 g of CCl4 to produce AsCl3 and CCl2F2. The theoretical yield of CCl2F2 produced, in
Kamila [148]
The chemical reaction would be written as 

2 AsF3<span> + 3 CCl4 = 2 AsCl3 + 3 CCl2F2
</span>
We use the given amounts of the reactants to first find the limiting reactant. Then use the amount of the limiting reactant to proceed to further calculations.

150 g AsF3 ( 1 mol / 131.92 g) = 1.14 mol AsF3
180 g CCl4 (1 mol / 153.82 g) = 1.17 mol CCl4

 Therefore, the limiting reactant would be CCl4 since it would be consumed completely. The theoretical yield would be:

1.17 mol CCl4 ( 3 mol CCl2F2 / 3 mol CCl4 ) = 1.17 mol CCl2F2

7 0
3 years ago
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