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3 years ago

Compare a crystal lattice with a molecule. What does the formula unit Al(OH)3 tell you about the compound aluminum hydroxide?

2 answers:

4 0

Molecules are made up by chemically bonding two or more atoms of the same element or different elements, they don’t have charge, and the atoms are bonded by covalent bonds. Lattices have a three- dimensional ordered arrangement of basic units (that can be an atom, molecule or an ion). Lattices are crystalline structures with these repeated basic units. When ions joined with ionic bonds, they form ionic crystals. The formula unit tells us that aluminium hydroxide has a crystal structure made from molecules.

Annette [7]3 years ago

3 0

Answer:

A crystal lattice is a solid in which the particles are arranged in a regular, repeating pattern.

A molecule is a discrete unit of atoms that is bonded together.

Many ions come together to form a crystal.

The formula unit of an ionic compound represents the smallest ratio of ions in the crystal.

The lattice of aluminum hydroxide has three OH- ions for every Al3+ ion.

Explanation:

any of those are right

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Shape of the periodic table

lora16 [44]

Answer:

Irregular spiral.....

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3 years ago

What is the correct answer to complete the table for L? * 0 1 -1 O 2 -2

lana66690 [7]

Explanation:

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4 years ago

The law of _______ of energy states that energy cannot be created or destroyed. A. transformation B. absorption C. stability D.

34kurt

The correct answer is D. Conservation

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4 years ago

Fe2O3 + 5C + 3O2 = 2Fe + 5CO2

tangare [24]

Answer:

0.33 mol of Fe₂O₃

Explanation:

For the reaction given in the question -

Fe₂O₃ + 5 C + 3O₂ → 2 Fe + 5 CO₂

Balancing the above reaction ,

2Fe₂O₃ + 5 C + 3O₂ → 2 Fe + 5 CO₂

According to the above balanced reaction ,

2 mol of Fe₂O₃ will react with 5 mol of C and 3 mol of O₂ to give 2 mol of Fe and 5 mol of CO₂ .

Hence ,

2 mol of Fe₂O₃ will react with 3 mol of O₂

or ,

3 mol of O₂ ------ 2 mol of Fe₂O₃

Using unitary method ,

1 mol of O₂ ------ 2 / 3 mol of Fe₂O₃

From the question , for 0.49 mol of O₂ ,

0.49 mol of O₂ ------- 2 / 3 * 0.49 mol of Fe₂O₃ = 0.33 mol of Fe₂O₃

3 0

3 years ago

Gaseous methane (CH4) will react with gaseous oxygen (O2) to produce gaseous carbon dioxide (CO) and gaseous water (H2O) . Suppo

Leto [7]

Answer:

0 g.

Explanation:

Hello,

In this case, since the reaction between methane and oxygen is:

$CH_4+2O_2\rightarrow CO_2+2H_2O$

If 0.963 g of methane react with 7.5 g of oxygen the first step is to identify the limiting reactant for which we compute the available moles of methane and the moles of methane consumed by the 7.5 g of oxygen:

$n_{CH_4}=0.963gCH_4*\frac{1molCH_4}{16gCH_4}=0.0602molCH_4\\ \\n_{CH_4}^{consumed}=7.5gO_2*\frac{1molO_2}{32gO_2}*\frac{1molCH_4}{2molO_2} =0.117molCH_4$

Thus, since oxygen theoretically consumes more methane than the available, we conclude the methane is the limiting reactant, for which it will be completely consumed, therefore, no remaining methane will be left over.

$left\ over=0g$

Regards.

7 0

3 years ago