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3 years ago

Compare a crystal lattice with a molecule. What does the formula unit Al(OH)3 tell you about the compound aluminum hydroxide?

2 answers:

4 0

Molecules are made up by chemically bonding two or more atoms of the same element or different elements, they don’t have charge, and the atoms are bonded by covalent bonds. Lattices have a three- dimensional ordered arrangement of basic units (that can be an atom, molecule or an ion). Lattices are crystalline structures with these repeated basic units. When ions joined with ionic bonds, they form ionic crystals. The formula unit tells us that aluminium hydroxide has a crystal structure made from molecules.

Annette [7]3 years ago

3 0

Answer:

A crystal lattice is a solid in which the particles are arranged in a regular, repeating pattern.

A molecule is a discrete unit of atoms that is bonded together.

Many ions come together to form a crystal.

The formula unit of an ionic compound represents the smallest ratio of ions in the crystal.

The lattice of aluminum hydroxide has three OH- ions for every Al3+ ion.

Explanation:

any of those are right

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A 0.300 m solution of hcl is prepared by adding some 1.50 m hcl to a 500 ml volumetric flask and diluting to the mark with deion

liberstina [14]

In dilution we add distilled water to decrease the concentration of required sample from high concentration to lower concentration
The law used for dilution:
M₁V₁]Before dilution = M₂V₂] After dilution
M₁ = 1.5 M
V₁ = ?
M₂ = 0.3 M
V₂ = 500 ml
1.5 * V₁ = 0.3 * 500 ml
so V₁ = 100 ml and it completed to 500 ml using 400 ml deionized water

8 0

3 years ago

If 0.580 moles of a monoprotic weak acid (ka = 7.4 10-5 is titrated with naoh, what is the ph of the solution at the half-equiva

Yuri [45]

S is for soil,cl (sometimes c) represents climate,o organisms including humans,r relief,p parent material, or lithology, andt time.

7 0

3 years ago

The rate constant for the second-order reaction 2NOBr(g) ¡ 2NO(g) 1 Br2(g) is 0.80/M ? s at 108C. (a) Starting with a concentrat

Valentin [98]

Answer:

(a)

$0.0342M$

(b)

$t_{1/2}=17.36s\\t_{1/2}=23.15s$

Explanation:

Hello,

(a) In this case, as the reaction is second-ordered, one uses the following kinetic equation to compute the concentration of NOBr after 22 seconds:

$\frac{1}{[NOBr]}=kt +\frac{1}{[NOBr]_0}\\\frac{1}{[NOBr]}=\frac{0.8}{M*s}*22s+\frac{1}{0.086M}=\frac{29.3}{M}\\$

$[NOBr]=\frac{1}{29.2/M}=0.0342M$

(b) Now, for a second-order reaction, the half-life is computed as shown below:

$t_{1/2}=\frac{1}{k[NOBr]_0}$

Therefore, for the given initial concentrations one obtains:

$t_{1/2}=\frac{1}{\frac{0.80}{M*s}*0.072M}=17.36s\\t_{1/2}=\frac{1}{\frac{0.80}{M*s}*0.054M}=23.15s$

Best regards.

8 0

3 years ago

Read 2 more answers

1. Is this equation balanced? Explain your answer. Na + Cl2 → NaCl ?

Delvig [45]

It is not balanced since there are 2 Cl molecules on the left side, and only 1 on the right side. In order to balance this, you would need to make sure there are the same amount of all the molecules on both sides...

4Na + 2Cl2 = 4NaCl

Hope this helps :)

3 0

3 years ago

How much energy is needed to vaporize 75.0 g of diethyl ether (c4h10o) at its boiling point (34.6°c), given that δhvap of diethy

malfutka [58]

Answer: 26.8 kJ of energy is needed to vaporize 75.0 g of diethyl ether

Explanation:

First we have to calculate the moles of diethyl ether

$\text{Moles of diethyl ether}=\frac{\text{Mass of diethyl ether}}{\text{Molar mass of diethyl ether}}=\frac{75.0g}{74g/mole}=1.01moles$

As, 1 mole of diethyl ether require heat = 26.5 kJ

So, 1.01 moles of diethyl ether require heat = $\frac{26.5}{1}\times 1.01=26.8kJ$

Thus 26.8 kJ of energy is needed to vaporize 75.0 g of diethyl ether

5 0

4 years ago