Initial cost = $30,000
Depreciation rate = 2.5%
Depreciation expense per year = 30,000*2.5/100 = $750
In six years,
Depreciation = 6*750 = $4,500
Value of the tractor = Initial cost - Depreciation = $30,000 - $4,500 = $25,500
Answer:
<h3>1. t=10</h3><h3>2. t=4</h3><h3>3. t=40</h3>
Step-by-step explanation:
Isolate the term of t from one side of the equation.
<h3>1. 4t=40</h3>
First, you have to divide by 4 from both sides.
4t/4=40/4
Solve.
Divide the numbers from left to right.
40/4=10
<h3><u>
t=10</u></h3>
<h3>2. 10+t=14</h3>
<u>First, change sides.</u>
t+10=14
<u>Then, subtract by 10 from both sides.</u>
t+10-10=14-10
<u>Solve.</u>
<u>Subtract the numbers from left to right.</u>
14-10=4
<h3><u>
t=4</u></h3>
<h3>3. 70-t=30</h3>
First, subtract by 70 from both sides.
70-t-70=30-70
Solve.
30-70=-40
<u>Rewrite the problem down.</u>
-t=-40
Divide by -1 from both sides.
-t/-1=-40/-1
<u>Solve.</u>
<u />
<u>Divide the numbers from left to right.</u>
-40/-1=40
<h3><u>
t=40</u></h3>
- <u>Therefore, the correct answer is t=10, t=4, and t=40.</u>
I hope this helps! Let me know if you have any questions.
So lets try to prove it,
So let's consider the function f(x) = x^2.
Since f(x) is a polynomial, then it is continuous on the interval (- infinity, + infinity).
Using the Intermediate Value Theorem,
it would be enough to show that at some point a f(x) is less than 2 and at some point b f(x) is greater than 2. For example, let a = 0 and b = 3.
Therefore, f(0) = 0, which is less than 2, and f(3) = 9, which is greater than 2. Applying IVT to f(x) = x^2 on the interval [0,3}.
Learn more about Intermediate Value Theorem on:
brainly.com/question/11377865
#SPJ4
Answer:
-18
Step-by-step explanation:
The answer is -18 because a negative plus a positive is always a negative.
Answer:
C.No, because each lime will cost a bit more than 30¢, so 4 limes will cost a bit more than $1.20.Step-by-step explanation:
