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3 years ago

Find the area of the white region

Mathematics

1 answer:

klemol [59]3 years ago

3 0

Answer:

Area = 51.89cm^2

Step-by-step explanation:

$The- region- is- a -segment\\r = 7cm\\\alpha = 150\\A = \frac{\alpha }{360} \times \pi r^2 -\frac{1}{2} \times r^2Sin\alpha \\\\A = \frac{150}{360} \times 3.142 \times7^2 -\frac{1}{2} \times 7^2 \times Sin 150\\A =5/12 \times 3.142 \times49- (1/2\times 49 \times1/2)\\A = 64.149-49/4\\A = 51.89$

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Pleaseeeee help im horrible at math

Murljashka [212]

Answer:

The Answer is gonna be D. 2

This is the right Answer:3

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3 years ago

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If a lawn measures 40 and 4/5 ft by 50 and 7/8ft how many square feet of seed will he need?

pychu [463]

So convert to improper fracitons (improper=x/y where x>y and the current one is mixed where it is in t s/f form) so

40 and 4/5=(40 times 5)/5 and 4/5=200/5 and 4/5=204/5

50 and 7/8=(50 times 8)/8 and 7/8=400/8 and 7/8=407/8

area=legnth times width
legnth =407/8
width=204/5
multiply 407/8 and 204/5

407/8 times 204/5=(407 times 204)/(8 times 5)=83028/40=2075.7 square feet

the answer is 2075.7 ft^2 of seed

6 0

3 years ago

Read 2 more answers

The length of a swimming pool is 3 feet longer than it’s width. The swimming pool is surrounded by a deck that is 2 feet wide an

Firlakuza [10]

Answer:

The Length of swimming pool is 8.35 feet

The width of swimming pool is 5.35 feet

Step-by-step explanation:

Given as :

The length of swimming pool is 3 feet longer that its width

Let The width of swimming pool = w feet

So, The Length of swimming pool = L = (w + 3) feet

Now, The swimming pool is surrounded by deck of 2 feet wide

The width of deck = w' = w + 2 + 2 = (w + 4) feet

The area of deck = 116 feet²

The length of deck = L' = L + 2 + 2 = (L + 4) feet

So, L' = (w + 3 + 4) feet

I.e L' = (w + 7) feet

∵ The area of deck = 116 feet²

So , L' × w' = 116 feet²

(w + 7)× (w + 4) = 116

Or, w² + 4 w + 7 w + 28 = 116

Or, w² + 11 w - 88 = 0

Solving the quadratic equation as

ax² + bx + c = 0

So, w = $\dfrac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}$

Or, w = $\dfrac{-11\pm \sqrt{11^{2}-4\times 1\times (-88)}}{2\times 1}$

Or, w = $\dfrac{-11\pm \sqrt{473}}{2}$

or, w = $\dfrac{-11\pm 21.7}{2}$

or, w = 5.35 , -16.35

The width of swimming pool = w = 5.35 feet

The Length of swimming pool = L = (5.35 + 3) feet = 8.35 feet

Hence, The Length of swimming pool is 8.35 feet

And The width of swimming pool is 5.35 feet

Answer

3 0

4 years ago

Which sentence represents the inequality -2b + 7 > 27.5?

USPshnik [31]

Answer:

C , negative two times a number, plus seven , is fewer than twenty-seven and five tenths 

6 0

3 years ago

Select True or False from each pull-down menu, depending on whether the corresponding statement is true or false.

Schach [20]

Answer:

1) FALSE

2) FALSE

3) TRUE

4) TRUE

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part 1

The mean and standard deviation of a normally distributed random variable which has been standardized are one and zero, respectively.

The mean and the deviation for the normal standard distribution are:

$\mu=0, \sigma =1$

So then that's FALSE.

Part 2

Using the standard normal curve, the z−score representing the 10th percentile is 1.28.

We are looking for a value a, that satisfy this:

$P(X>a)=0.90$ (a)

$P(X$ (b)

We can find a z value that satisfy the condition with 0.10 of the area on the left and 0.90 of the area on the right it's z=-1.28. On this case P(Z<-1.28)=0.10 and P(Z>-1.28)=0.90

So that's FALSE.

Part 3

Let z1 be a z−score that is unknown but identifiable by position and area. If the symmetrical area between −z1 and +z1 is 0.9544, the value of z1 is 2.0

If we find this probability:

$P(-2.0< Z$

So on this case we can approximate to 0.9544. And that's TRUE.

Part 4

Using the standard normal curve, the z−score representing the 75th percentile is 0.67.

We are looking for a value a, that satisfy this:

$P(X>a)=0.25$ (a)

$P(X$ (b)

We can find a z value that satisfy the condition with 0.75 of the area on the left and 0.25 of the area on the right it's z=0.67. On this case P(Z<0.67)=0.75 and P(Z>0.67)=0.25

So that's TRUE.

3 0

3 years ago