Answer:
41.44 g
Explanation:
First of all, we must put down the equation of the reaction;
Number of moles of CaO = 33g/56 g/mol = 0.59 moles
Number of moles of H20 = 10g/18 g/mol = 0.56 moles
Since the reaction is in 1:1 mole ration, H2O is the limiting reactant
Hence;
mass of Ca(OH)2 produced = 0.56 moles * 74 g/mol = 41.44 g
Explanation:
Moles of N2 = 35.0g / (28g/mol) = 1.25mol
Moles of H2 = 60.0g / (2g/mol) = 30.0mol
Since 1.25mol * 3 < 30.0mol, nitrogen is limiting.
Moles of NH3 = 1.25mol * 2 = 2.50mol.
Mass of NH3 = 2.50mol * (17g/mol) = 42.5g.
30.0mol - 1.25mol * 3 = 26.25mol.
Excess mass of H2
= 26.25mol * (2g/mol) = 52.5g.
Answer:
The correct answer to this problem is B. 7.0 X 10^-8 meters
Explanation:
To solve this problem, we have to use the following equation:
c = λν, or speed of light = wavelength*frequency
If we substitute in the values we are given by the problem, we get:
3.00 * 10^8 m/s = (4.3 * 10^15 Hz)*(wavelength)
wavelength = 6.98 * 10^-8 m
Since the given value has 2 significant figures, our answer should similarly include two significant figures since the operation in the problem was multiplication.
Therefore, the answer is B. 7.0 X 10^-8 meters.
Hope this helps!
Answer:
CaF2
Explanation:
1 mole of CaF2 = 78.0748064 grams
78 times 3.33= 259.74
the others multiplied were nowhere near 260 grams either
