Answer: An existing theory is modified so that it can explain both the old and new observations.
Explanation:
Answer:
The answer is "12.06"
Explanation:
Given:
6 mmol of both will react
excess KOH remaining
Volume
![[OH^{-}] = \frac{ 9.6 \ mmol}{84\ mL} = 0.01142\ M](https://tex.z-dn.net/?f=%5BOH%5E%7B-%7D%5D%20%3D%20%5Cfrac%7B%209.6%20%5C%20mmol%7D%7B84%5C%20%20mL%7D%20%3D%200.01142%5C%20M)
use:
![pOH = -\log [OH^-]](https://tex.z-dn.net/?f=pOH%20%3D%20-%5Clog%20%5BOH%5E-%5D)
use:
Answer:
For the purposes of your question, we can think of speed and velocity as being the same thing. Therefore, the potential energy of an object is proportional to the square of its velocity (speed). In other words, If there is a twofold increase in speed, the potential energy will increase by a factor of four.
Answer:
yes, a compound can have more than one carbon-carbon double bond
<u>Answer and Explanation:</u>
Mercury combines with sulfur as follows -
Hg + S = HgS
Hg = 200,59
S = 32,066 Therefore 1.58 g of Hg will react with -
1.58 multiply with 32,066 divide by 200,96 of sulfur.
= 0.25211 g S
This will form 1.58 + 0.25211 g HgS = 1.83211 g HgS
The amount of S remaining = 1.10 - 0.25211 = 0.84789 g
