The specific heat of the metal, given the data from the question is 0.60 J/gºC
<h3>Data obtained from the question </h3>
The following data were obtained from the question:
- Mass of metal (M) = 74 g
- Temperature of metal (T) = 94 °C
- Mass of water (Mᵥᵥ) = 120 g
- Temperature of water (Tᵥᵥ) = 26.5 °C
- Equilibrium temperature (Tₑ) = 32 °C
- Specific heat capacity of the water (Cᵥᵥ) = 4.184 J/gºC
- Specific heat capacity of metal (C) =?
<h3>How to determine the specific heat capacity of the metal</h3>
The specific heat capacity of the sample of gold can be obtained as follow:
According to the law of conservation of energy, we have:
Heat loss = Heat gain
MC(T –Tₑ) = MᵥᵥC(Tₑ – Tᵥᵥ)
74 × C(94 – 32) = 120 × 4.184 (32 – 26.5)
C × 4588 = 2761.44
Divide both side by 4588
C = 2761.44 / 4588
C = 0.60 J/gºC
Thus, the specific heat capacity of the metal is 0.60 J/gºC
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Brass is an alloy, or a combination of two (or more) metals.
Answer:
IHD = 0; no unsaturation in the formula
Explanation:
The IHD is also known as the degree of unsaturation formula. This formula is commonly used to get an idea of how many unsaturations a molecule has, and in this way, we can get an approach of the type of compound we are treating. For example, if this number is 1, it means that the compound has at least one unsaturation and it could be a double bond or just cyclical compound.
The IHD is calculated using the following expression:
IHD = (a + 1) - (b + x - c)/2 (1)
Where:
a: number of carbon
b: number of hydrogens
c: humber of nitrogens
x: number of halogens.
Now, we have the formula C₄H₉Cl, let's identify a, b, c and x:
a: 4 carbons; b = 9 hydrogens; C = none; X: 1 chlorine
Replacing in (1) we have:
IHD = (4+1) - (9+1)/2
IHD = 5 - (10/2)
<h2>
IHD = 0</h2>
So this number is 0, which means that the molecule does not have any kind of unsaturation (Non double bond, multi bond or cyclical).
Hope this helps
<em>please</em><em> </em><em>wait </em><em>I </em><em>am </em><em>answering</em>
Answer:
The answer is C. Gamma rays are the highest energy electromagnetic waves in the electromagnetic ... Show the heat released by astronomical objects 3. Detect collection of gas, dust, and plasma. Which of these best matches the waves with their applications? ... C) Gamma rays—1 and infrared waves—2