Explanation:
Relation between pressure, latent heat of fusion, and change in volume is as follows.
Also, 
where, 
is the difference in specific volumes.
Hence, 
As, 
= 22.0 J/mol K
And, 
...... (1)
where, 
= density of water
= density of ice
M = molar mass of water = 
Therefore, using formula in equation (1) we will calculate the volume of fusion as follows.
= 
= 
Therefore, calculate the required pressure as follows.
= 
or, = 145 bar/K
Hence, for change of 1 degree pressure the decrease is 145 bar and for 4.7 degree change dP = 
= 681.5 bar
Thus, we can conclude that pressure should be increased by 681.5 bar to cause 4.7 degree change in melting point.
A.) 1.
b.) 3
c.) 2
I hope this helps.
<u>Answer:</u> The correct answer is Option A.
<u>Explanation:</u>
A catalyst is defined as the substance which increases the rate of the reaction without actually participating in the reaction.
This substance decreases the activation energy of the reactants, so as to proceed the reaction at a faster rate by increasing their effective collisions.
It does not affect the concentration of the reactants.
For the given reaction:
If we add NO, which is acting as a catalyst will increase the rate of the reaction to produce the products which is 
Hence, the correct answer is Option A.
"C6H12O6 and HC2H3O2" is the one pair among the following choices given in the question in which both <span>compounds have the same empirical formula. The correct option among all the options that are given in the question is the fourth option or option "D". I hope the answer has come to your great help.</span>
Answer:
0.96g of sodium hydride
Explanation:
Equation of reaction:
NaH + H20 = NaOH + H2
Mass of hydrogen gas produced (m) = PVM/RT
P = 765torr - 28torr = 737torr = 737/760 = 0.97atm, V = 982mL = 982cm^3, M = 2g/mol, R = 82.057cm^3.atm/gmol.K, T = 28°C = 28 + 273K = 301K
m = (0.97×982×2)/(82.057×301) = 0.08g of hydrogen gas
From the equation of reaction
1 mole (24g) of sodium hydride produced 1 mole (2g) of hydrogen gas
0.08g of hydrogen gas would be produced by (24×0.08)/2 = 0.96g of sodium hydride
