Find the product:
3j^2-4j-6j-8
Simplify:
3j^2-10j-8
Answer:
<h2><u>Solution</u><u> </u><u>:</u><u>-</u></h2>
In figure 1 value of y is 1
In figure 2 value of y is 6
In figure 3 value of y is 5

First of all, the minus sign before the parenthesis changes the sign of all the terms inside:

Now, we can sum like terms:

So, the final expression is

Answer:
- (a-2)(3a-5)
- (b-3)(5b-17)
Step-by-step explanation:
Recognize that b-a = -(a-b). (Reversing the order of a difference changes its sign.)
1. 3(a-2)² -(2-a) = 3(a-2)² +(a-2) = (a-2)(3(a-2) +1)
... = (a -2)(3a -5)
2. 2(3-b) +5(b-3)² = (b -3)(-2 +5(b -3))
... = (b -3)(5b -17)