Answer:
A dominant allele is denoted by a capital letter (A versus a).Since each parent provides one allele, the possible combinations are: AA, Aa, and aa. Offspring whose genotype is either AA or Aa will have the dominant trait expressed phenotypically, while aa individuals express the recessive trait.
After 20 years a resorted wetland can contain approx. 80% of plant biomass of a natural wetland.
Wetlands are one of the most endangered ecosystems in the world according to the UN and restoration is the only way to save these habitats.
The fact that restored wetlands can contain up to 80% of plant biomass shows how successful restoration programs can be.
The given question is incomplete. The complete question is as follows;
The number of bacteria in a certain population is predicted to increase according to a continuous exponential growth model, at a relative rate of 16% per hour. Suppose that a sample culture has an initial population of 71 bacteria. Find the predicted population after three hours Do not round any intermediate computations, and round your answer to the nearest tenth bacteria
.
Answer:
114.7
Explanation:
A (t) represent the population of the bacteria at the time t.
Since, the population grows exponentially, the population can be calculated as follows:
A (t) = Ao × 
A (t) is teh final population, Ao is the initial population, e is the exponential, k is rate and t is time.
A (t) = 71 × 
For t = 3 hours
A (t) = 71 × 
A (t) = 114.7.
The population of bacteria after 3 hours is 114.7.
Multiply 5730 years by 2 since two half-lives have gone by for carbon.
<u>Explanation</u>:
The half-life of a radioactive isotope depicts the measure of time that it takes half of the isotope in an example decay. On account of radiocarbon dating, the half-existence of carbon 14 is 5,730 years
The half-life of carbon-14 is 5730 years.
In this manner, after
1 half-life there is 50 % = 1/2 of the first amount left.
2 half-lives there is 25 % = 1/4 of the first amount left.
25% is two half-lives.
Every 50% of life requires 5730 years.
So two half-lives require 2 × 5730