Step-by-step explanation:
A study was to be undertaken to determine if a particular training program would improve physical fitness. A sample of 31 university students was selected to be enrolled in the fitness program. The researchers wished to determine if there was evidence that their sample of students differed from the general population of untrained subjects. The sample mean is 47.4 and a standard deviation of 5.3. The 98% confidence interval is determined and is given as, (45.2, 49.6) .
If the level of confidence is changed to 95%, then the confidence interval will become shorter but the p-value will not change because it is calculated using the test statistic. So the correct answer is (a).
The value of a where the Limit of g(x) as x approaches alpha not exist are -1 and 1
<h3>Limit of a function</h3>
The limit of a function is the limit of a function as x tends to a value.
From the given graph, you can see that the function g(x) goes large at the point where the arrows orange and purple point down from the x-coordinates -1 and 1.
Hence the value of a where the Limit of g(x) as x approaches alpha not exist are -1 and 1
Learn more on limit of a function here: brainly.com/question/23935467
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Question 1:
"Match" the letters
DE are the last two letters of BCDE
The last two letters of OPQR is QR
DE is congruent to QR
Question 2:
Blank 3: Reflexive property (shared side)
Blank 4: SSS congruence of triangles (We have 3 sets of congruent sides)
Question 3:
I'm guessing those two numbers are 7.
Since both are 7, AB and AE are congruent.
We know that all the other sides are congruent because it is given.
We also know that there is a congruent angle in each triangle.
Thus, the two triangles are congruent by SAS or SSS.
(Note: I couldn't prove this without the two "7"s because there is no such thing as SSA congruence)
Have an awesome day! :)
Given :
Miki has 104 nickels and 88 dimes.
She wants to divide her coins into groups where each group has the same number of nickels and the same number of dimes.
To Find :
Largest number of groups she can have .
Solution :
In the given question we need to find the largest number of groups she can have i.e we have to find the LCM of 104 and 88 .
Now , factorizing both of them , we get :
Form above , we can say that common factors are :
Therefore , the largest number of groups she can have is 8 .
Hence , this is the required solution .
