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goldenfox [79]
3 years ago
6

Someone please help me!!!!what’s the answer????

Mathematics
1 answer:
Marta_Voda [28]3 years ago
7 0

Answer:

Bad quality and u should´ve payed attention in class

Step-by-step explanation:

....

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Mr. Christensen is arranging his students into groups for the next school debate. When he puts them in groups of 5, two students
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The least amount of students mr Christensen has would be 5 because if he puts them in a group of 4 and one is left out that would equal to 5.
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Help someone please!! Ty
erma4kov [3.2K]

Answer:

Option (B)

Step-by-step explanation:

Let the five distinct positive integers are a, b, c, d, e.

Average of these five integers is 20.

\frac{a+b+c+d+e}{5}=20

a + b + c + d + e = 100

If these integers are in the increasing order,

Median of these integers 'c' = 12

If the sum of d and e is the largest then the sum of a and b will be the smallest.

Therefore, the smallest positive integers a and b will be,

a = 1 and b = 2

1 + 2 + 12 + d + e = 100

15 + d + e = 100

d + e = 100 - 15

d + e = 85

Since d will be greater than the median c,

d > c

d > 12

For the largest value of integer 'e', value of 'd' will be minimum.

The least value of d will be = 13

Then, 13 + e = 85

e = 85 - 13

e = 72

{a, b, c, d, e} = {1, 2, 12, 13, 72}

Therefore, the largest possible number is this set will be 72.

Option (B) will be the answer.

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