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castortr0y [4]
3 years ago
9

How would you graph 6x-5y=-13

Mathematics
1 answer:
castortr0y [4]3 years ago
3 0
It might help to convert this to slope-intercept form:

6x - 5y = -13
-5y = -6x - 13
5y = 6x + 13
y = 6/5x + 13/5

There is a slope of 6/5 and a y-intercept of 13/5. Two possible points on the line could be (0, 13/5) and (2, 5). You only need two points to define a line.
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A.(x, y) (x -1, y + 4)
attashe74 [19]
The answer is D i believe
8 0
2 years ago
Read 2 more answers
Solve the system of equations.
Xelga [282]

Answer:

  b.  x=1, y=2, z=3

Step-by-step explanation:

The system of equations ...

  • 3x +2y +z = 10
  • 9x -6y +z = 0
  • x -y -3z = -10

has solution (x, y, z) = (1, 2, 3) . . . . matches choice B.

_____

While it is convenient to solve this using a graphing calculator or web site, one can easily solve the system by hand.

Subtract the second equation from 3 times the first:

  3(3x +2y +z) -(9x -6y +z) = 3(10) -(0)

  12y + 2z = 30 . . . . simplify

Dividing this result by 2 gives ...

  6y +z = 15 . . . . . . [eq4]

Subtract 3 times the third equation from the first:

  (3x +2y +z) -3(x -y -3z) = (10) -3(-10)

  5y +10z = 40 . . . . simplify

  y + 2z = 8 . . . . . . . divide by 5 . . . . . [eq5]

The two equations [eq4] and [eq5] can be solved any of the ways you usually solve two equations in two variables. Here, we'll use the first equation to write an expression for z that we can substitute into the second equation.

  z = 15 -6y . . . . . subtract 6y from [eq4]

  y + 2(15 -6y) = 8 . . . . . substitute for z in [eq5]

  -11y +30 = 8 . . . . . simplify

  -11y = -22 . . . . . . . subtract 30

  y = 2 . . . . . . . . . . . divide by the coefficient of y

  z = 15 -6(2) = 3 . . . . substitute for y in our equation for z

Substituting these values for y and z into the third original equation gives ...

  x - 2 -3(3) = -10

  x -11 = -10 . . . . . . . . simplify

  x = 1 . . . . . . . . . . . . add 11

The solution to the above system of equations is (x, y, z) = (1, 2, 3).

_____

<em>Comment on the problem statement</em>

Math is generally unforgiving of imprecision. The given system of equations has no variable "z", and some other typos are apparently involved. That is why we rewrote the system to the equations shown above.

It is very easy to mistake z for 2, or g for 9, or o for 0, or 1 for 7. There are other confusions that are possible, as well. Letters I (eye) and l (ell) are easily confused, and may be confused with 1 (one) as well. Sometimes y and 4, or 4 and 9, can also be written so as to be difficult to tell apart. Great care must be taken when handwriting these symbols.

7 0
3 years ago
I need some help with this rational equation. It's supposed to = -1, but for some strange reason I keep getting x^2 +2x = -1.
Rasek [7]

This one is so easy that your brain refuses to accept it.
It's looking for a harder answer, but can't find it !

You're totally correct, as far you went.     x² + 2x does = -1

Now add ' 1 ' to each side:     x² + 2x + 1 = 0

Can you factor that quadratic ?
Can you mash it through the quadratic formula ?

Actually, it's the simplest possible perfect square.

                                       x² + 2x + 1  =  (x + 1)²

So the solutions of     x² + 2x + 1 = 0  are both   x = -1 .

Don't say anything.
I know it's embarrassing.

7 0
3 years ago
Please help me with this math question
Volgvan
Ur answer is : h(d) = 2d + 3

because if u sub in the points in ur table, this equation works....with the number of months being d and the length of the hair being h(d)
8 0
3 years ago
Is this decimal closer to 10 or 20?
PIT_PIT [208]

Answer:

Its closer to 10

Step-by-step explanation:

5 0
3 years ago
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