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Aleks [24]
4 years ago
12

A truck drove at an average rate of 45 miles per hour on the highway and 20 miles per hour once it entered the city. If it took

the trip, which was 100 miles, in 3 hours, how much of it was in the city?
Mathematics
2 answers:
SIZIF [17.4K]4 years ago
7 0
45 * 1.6 + 20 * 1.4 = 100
72 + 28 = 100
100 = 100
denis-greek [22]4 years ago
4 0

Answer:

28

Step-by-step explanation:

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Given f(x) = 3x2 + kx – 7, and the remainder when f (x) is divided by x – 4 is
USPshnik [31]

Answer:

-243

Step-by-step explanation:

{3׳ykx-7 incluye

7 0
2 years ago
Write the fracción which corresponds to the part no shaded
Andru [333]

Answer:

1/6

Step-by-step explanation:

There are 6 large squares here, all of which have been shaded but for one.

Thus, the desired fraction is 1/6.

8 0
3 years ago
What is the solution to this equation x/5=15<br> a.x=75<br> b.x=20<br> c.x=3<br> d.x=10
Darina [25.2K]

\dfrac{x}{5}=15\ \ \ \ |\cdot5\\\\\not5\cdot\dfrac{x}{\not5}=5\cdot15\\\\x=75

Answer: a. x = 75

8 0
3 years ago
(Hehe...Please ignore the markings)
inysia [295]

Answer:

See below:

Step-by-step explanation:

Problem 1:

Multiply Equation 1 by 4, keep Equation 2 the same.

x+y=8, multiply each term by 4:

4*x=4x, 4*y=4y, 8*4=32

so, the equivalent system is: 4x+4y=32 and x-y=2

Solve the system of equations:

x-y=2 becomes x=y+2

plug into 4x+4y=32 to solve for y

4(y+2)+4y=32---> 4y+8+4y=32--->8y=24---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 1 Answer:

Equivalent system: 4x+4y=32, x-y=2; solution: x=5, y=3

Problem 2:

Keep Equation 1 the same. Add 1 and 2.

To add an equation, add the left sides together, and then the rights.

so: x+y=8 + x-y=2 gives us: 2x=10

solve for x ---> 2x/2=10/2--->x=5

plug x into x+y=8--->5+y=8--->y=3

Problem 2 answer:

Equivalent system: x+y=8, 2x=10; solution:x=5, y=3

Problem 3:

Subtract Equation 2 from 1, and keep 2 the same.

To subtract an equation, subtract the left sides, then the rights. We are subtracting 1<em> from </em>2, so its 2-1.

x-y=2 - x+y=8 gives us: -2y=-6

Solve for y by dividing by -2-->-2y/-2=-6/-2---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 3 answer:

Equivalent system: -2y=-6, x-y=2; solution: x=5, y=3

Problem 4:

Multiply the sum of Equation 1 and 2 by a factor of 3. Keep equation 2 the same.

First we add 1 and 2: (we did this earlier) ---> 2x=10 ---> now we multiply it all by 3---> 2x*(3)=10*(3)---> this gives us: 6x=30---> now divide by 6 to solve for x: 6x/6=30/6 gives us: x=5

Now, solve for y by plugging x into equation 2: x-y=2---> 5-y=2--->y=3

Problem 4 answer:

Equivalent system: 6x=30, x-y=2; solution: x=5, y=3

______

Quick Tip: One thing inherent of Equivalent systems is that they have the same set of solutions. Thus, we know the systems are equivalent when they have the same set of solutions for x and y. Moreover, you don't need to solve every time after you attempt to find an equivalent system, instead, just plug in the values found in problem 1 to each new set of equations to test if they are equivalent.

If we find x=5 and y=3 for x+y=8 and x-y=2, then all we have to do is plug them in to 6x=30 and -2y=-6 to see if they are equivalent.

6(5)=30 ---> true

-2(3)=-6 ---> true

3 0
3 years ago
Find the Measure of the missing angles.
Savatey [412]

Step-by-step explanation:

1= 118°+angle 1=180°

angle 1= 180°-118°=62°

angle 2=180°-135°=45°

angle 3=135°

8 0
3 years ago
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