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alexandr402 [8]
3 years ago
10

Tom bought a coat for £49 in a 30% off sale. How much money did he save?

Mathematics
2 answers:
motikmotik3 years ago
7 0

Answer:

£13 is what time saved . thank you

Serjik [45]3 years ago
6 0

Answer:

21 pounds

Step-by-step explanation:

30% off sale means the price was reduced to 70%

70% of the initial price is 49pounds

Initial price = x

0.7x = 49

x = 49/.07 = 70

Amount saved = 70 - 49 = 21 pounds

Please mark brainliest if helpful. Thanks

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75 percent of the sutdents in a school went on a field trip. If 285 students went on the trip, how any students are in the schoo
natita [175]

Answer:

380

Step-by-step explanation:

285 / x = 75 / 100

Cross multiply 28500 = 75x

Divide by 75  380

8 0
2 years ago
There are no universally accepted definitions of the ages of Millennials and Generation Xers; the consensus is that the former a
nadya68 [22]

Answer:

<u>A. The probability that a Millennial is married is 0.089 or 8.9%.</u>

<u>B. The probability that a Baby Boomer is single, never married is 0.03 or 3%.</u>

<u>C. The probability that one person selected randomly (female or male) is married is 0.513 or 51.3% </u>

<u>D. The probability that someone who is living with a partner, but not married is a Generation X is 0.025 or 2.5%.</u>

Step-by-step explanation:

According to the information provided on the analysis table, we can answer the questions:

A. The probability that a Millennial is married is 0.089 or 8.9%.

B. The probability that a Baby Boomer is single, never married is 0.03 or 3%.

C. The probability that one person selected randomly (female or male) is married is 0.513 or 51.3% (Millennial 0.089 + Generation X 0.223 + Baby boomer 0.201)

D. The probability that someone who is living with a partner, but not married is a Generation X is 0.025 or 2.5%.

7 0
3 years ago
Part 1
bearhunter [10]

Answer:

Sale price:$29.02

Step-by-step explanation:

32.5/100=0.325x43.00=13.975/13.98(rounded)

43.00-13.98=29.02

4 0
3 years ago
What is the inverse of the function f(x)=8x+1? f^{-1}(x)=
zysi [14]
Change the x and y
Then solve for y
X= 8y+1
Subtract 1 from both sides
X-1=8y
Divide by 8
X-1 /8 = y
4 0
3 years ago
This problem uses the teengamb data set in the faraway package. Fit a model with gamble as the response and the other variables
hichkok12 [17]

Answer:

A. 95% confidence interval of gamble amount is (18.78277, 37.70227)

B. The 95% confidence interval of gamble amount is (42.23237, 100.3835)

C. 95% confidence interval of sqrt(gamble) is (3.180676, 4.918371)

D. The predicted bet value for a woman with status = 20, income = 1, verbal = 10, which shows a negative result and does not fit with the data, so it is inferred that model (c) does not fit with this information

Step-by-step explanation:

to)

We will see a code with which it can be predicted that an average man with income and verbal score maintains an appropriate 95% CI.

attach (teengamb)

model = lm (bet ~ sex + status + income + verbal)

newdata = data.frame (sex = 0, state = mean (state), income = mean (income), verbal = mean (verbal))

predict (model, new data, interval = "predict")

lwr upr setting

28.24252 -18.51536 75.00039

we can deduce that an average man, with income and verbal score can play 28.24252 times

using the following formula you can obtain the confidence interval for the bet amount of 95%

predict (model, new data, range = "confidence")

lwr upr setting

28.24252 18.78277 37.70227

as a result, the confidence interval of 95% of the bet amount is (18.78277, 37.70227)

b)

Run the following command to predict a man with maximum values ​​for status, income, and verbal score.

newdata1 = data.frame (sex = 0, state = max (state), income = max (income), verbal = max (verbal))

predict (model, new data1, interval = "confidence")

lwr upr setting

71.30794 42.23237 100.3835

we can deduce that a man with the maximum state, income and verbal punctuation is going to bet 71.30794

The 95% confidence interval of the bet amount is (42.23237, 100.3835)

it is observed that the confidence interval is wider for a man in maximum state than for an average man, it is an expected data because the bet value will be higher than the person with maximum state that the average what you carried s that simultaneously The, the standard error and the width of the confidence interval is wider for maximum data values.

(C)

Run the following code for the new model and predict the answer.

model1 = lm (sqrt (bet) ~ sex + status + income + verbal)

we replace:

predict (model1, new data, range = "confidence")

lwr upr setting

4,049523 3,180676 4.918371

The predicted sqrt (bet) is 4.049523. which is equal to the bet amount is 16.39864.

The 95% confidence interval of sqrt (wager) is (3.180676, 4.918371)

(d)

We will see the code to predict women with status = 20, income = 1, verbal = 10.

newdata2 = data.frame (sex = 1, state = 20, income = 1, verbal = 10)

predict (model1, new data2, interval = "confidence")

lwr upr setting

-2.08648 -4.445937 0.272978

The predicted bet value for a woman with status = 20, income = 1, verbal = 10, which shows a negative result and does not fit with the data, so it is inferred that model (c) does not fit with this information

4 0
3 years ago
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