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3 years ago

Factor 25x^2 - 10x - 24

Mathematics

2 answers:

Romashka [77]3 years ago

8 0

(5x+4)(5x-6) is the correct answer

Triss [41]3 years ago

6 0

Answer:

(5x+4) (5x-6)

Step-by-step explanation:

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Mr. Freye distributed $126 equally among his 4 children for their weekly allowance how much money did each child receive?

mote1985 [20]

Answer:

$10.50

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

simplify the following expression: (x+7/4x) + (5/x-8) I also attached a photo of the problem if you get confused on how I typed

Gnoma [55]

Answer:

$\frac{x^{2} + 19x - 56}{4 {x}^{2} - 32x}$

Step-by-step explanation:

Start by making the denominators of both fraction the same. This can be done by multiplying one fraction's denominator by the other.

After simplifying and combining the two fractions together, check if the numerator can be factorised such that there is a common factor in the denominator and numerator. In this case, the numerator cannot be factorised.

Lastly, expand the denominator.

$\frac{x + 7}{4x} + \frac{5}{x - 8}$

$= \frac{(x + 7)(x - 8)}{4x(x - 8)} + \frac{5(4x)}{4x(x - 8)}$

$= \frac{x(x) + x( - 8) + 7(x) + 7( - 8) + 20x}{4x(x - 8)}$

$= \frac{ {x}^{2} - 8x + 7x - 56 + 20x }{4x(x - 8)}$

$= \frac{ {x}^{2} + 19x - 56}{4x(x - 8)}$

$= \frac{ {x}^{2} + 19x - 56}{4 {x}^{2} - 32x}$

7 0

2 years ago

NEEDs HELP AB ⊥ AC true or false idk i think it's false

jonny [76]

Perpendicular means the slopes are opposite inverse of each other
If line a is slope 2, the perpendicular line to Line a would have a slope - 1/2
Difference in y over difference in x gives slope. If they are opposite inverse values the lines are perpendicular. ( in this case the answer is true.)

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3 years ago

Six of 16 students in Mr. McConney's class are serving detentions, the rest are here for tutoring. What percent of students are

Ivan

Answer:

62.5%

Step-by-step explanation:

plz mark the brainliest

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3 years ago

Read 2 more answers

Integrate 1 - x / x(x2 + 1) d x by partial fractions.

solniwko [45]

Answer:

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

Step-by-step explanation:

step 1:- by using partial fractions

$[tex]\frac{1-x}{x(x^{2}+1) } =\frac{A(x^{2}+1)+(Bx+C)(x }{x(x^{2}+1) }$ ......(1)

step 2:-

solving on both sides

$1-x=A(x^{2} +1)+(Bx+C)x......(2)$

substitute x =0 value in equation (2)

1=A(1)+0

A=1

comparing x^2 co-efficient on both sides (in equation 2)

0 = A+B

0 = 1+B

B=-1

comparing x co-efficient on both sides (in equation 2)

-1 = C

step 3:-

substitute A,B,C values in equation (1)

now

$\\\int\limits^ {} \, \frac{1-x}{x(x^{2}+1) } d x =\int\limits^ {} \frac{1}{x} d x +\int\limits^ {} \frac{-x}{x^{2}+1 } d x -\int\limits \frac{1}{x^{2}+1 } d x$

by using integration formulas

i) by using $\int\limits \frac{1}{x} d x =log x+c........(a)\\\int\limits \frac{f^{1}(x) }{f(x)} d x= log(f(x)+c\\$ .....(b)

$\int\limits tan^{-1}x dx =\frac{1}{1+x^{2} } +C$ .....(c)

step 4:-

by using above integration formulas (a,b,and c)

we get answer is

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

6 0

3 years ago