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Maurinko [17]
3 years ago
14

What is the value of y? Enter your answer in the box. y = An isosceles triangle with vertices labeled A, B, and C. Side B C is t

he base. Sides A B and A C are equal. Sides A B and A C are labeled with single tick marks. Angle A is labeled as left parenthesis 4 y plus 10 right parenthesis degrees, angle B is labeled as 75 degrees, and angle C is labeled as left parenthesis 3 x right parenthesis degrees.
Mathematics
1 answer:
masha68 [24]3 years ago
5 0

Answer:

y = 5

Step-by-step explanation:

Given:

An isosceles triangle ABC with AB = AC.

∠A = (4y+10)\°

∠B = 75\°

∠C = (3x)\°

We know that, for an isosceles triangle, the angles opposite equal sides are also equal to each other.

Therefore, ∠B = ∠C

⇒ 75 = 3x

⇒ x=\frac{75}{3}=25

∴ ∠C = 3\times 25=75°

Now, the sum of all the interior angles of a triangle is always 180°.

\angle A + \angle B + \angle C=180\\(4y+10)+75+75=180\\4y+10+150=180\\4y+160=180\\4y=180-160\\4y=20\\y=\frac{20}{4}=5

Therefore, the value of 'y' is 5.

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Thus, x = 4 satisfies the inequality -2x < 10.

∴ x = 4 is the solution to the inequality -2x < 10.

FOR  -6 < -2x

substituting x = 4 in -6 < -2x

-6 < -2x

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Thus, x = 4 does not satisfiy the inequality -6 < -2x

∴ x = 4 is the NOT a solution to the inequality -6 < -2x.

Conclusion:

x = 4 is NOT a solution to both inequalites.

Part c) Find another value of x that is a solution to both inequalities.

<u>solving -2x < 10</u>

-2x\:

Multiply both sides by -1 (reverses the inequality)

\left(-2x\right)\left(-1\right)>10\left(-1\right)

Simplify

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\frac{2x}{2}>\frac{-10}{2}

x>-5

-2x-5\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-5,\:\infty \:\right)\end{bmatrix}

<u>solving -6 < -2x</u>

-6 < -2x

switch sides

-2x>-6

Multiply both sides by -1 (reverses the inequality)

\left(-2x\right)\left(-1\right)

Simplify

2x

Divide both sides by 2

\frac{2x}{2}

x

-6

Thus, the two intervals:

\left(-\infty \:,\:3\right)

\left(-5,\:\infty \:\right)

The intersection of these two intervals would be the solution to both inequalities.

\left(-\infty \:,\:3\right)  and \left(-5,\:\infty \:\right)

As x = 1 is included in both intervals.

so x = 1 would be another solution common to both inequalities.

<h3>SUBSTITUTING x = 1</h3>

FOR  -2x < 10

substituting x = 1 in -2x < 10

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-3(1) < 10

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TRUE!

Thus, x = 1 satisfies the inequality -2x < 10.

∴ x = 1 is the solution to the inequality -2x < 10.

FOR  -6 < -2x

substituting x = 1 in -6 < -2x

-6 < -2x

-6 < -2(1)

-6 < -2

TRUE!

Thus, x = 1 satisfies the inequality -6 < -2x

∴ x = 1 is the solution to the inequality -6 < -2x.

Conclusion:

x = 1 is a solution common to both inequalites.

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