Remaining area of poster = Area of Big rectangle - Area of small rectangle
= (36*24) - (5*12) =
= 864 - 60 = 804 in^2
The perimeter = 20 and AC = 8
Now as it is not mentioned which sides are equal of the isosceles triangle ABC,
We have two possible situations.
1)
If AC is the base
In that case AB = BC
Now AC = 8, AB = x , BC = x
So x + x + 8 = 20
2x + 8 = 20
2x = 12
x = 6
AB = BC = 6
2)
IF AC is not the base,
Then
AC = BC or AC = AB
So BC = 8 or AB = 8
If AB = AC = 8
Then
BC + 8 + 8 = 20
BC = 4
So there are two possible lengths of BC
Either it is BC = 8 or BC = 6 or BC = 4
The figure is attached for your reference.
Answer:
10v*3 =
30v
Step-by-step explanation:
That's the answer
1 inch =2.5cm
lenght =30.25×2.5=75.625cm
width = 21×2.5=52.5cm
area of painting = 75.625×52.5=3970.3125cm²