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3 years ago

Please help? I'm giving good points and will give brainiest and thanks.

Mathematics

1 answer:

zubka84 [21]3 years ago

3 0

Answer:

The difference in sales is that Hillary sold $2,400 more than Jon

Step-by-step explanation:

To find each of their sales, start by dividing the amount they made by the percentage of commission that they earn.

Hillary

3498/.22 = 15,900

Jon

3780/.28 = 13,500

So now to find the difference, we subtract Jon's total from Hillary's.

15,900 - 13,500 = 2,400

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F(x)=2x^2-x-6 g(x)=4-x (f+g)(x)

Semenov [28]

$\large \boxed{(f + g)(x) = f(x) + g(x)}$

The property above is distribution property where we distribute x-term in the function.

Substitute both f(x) and g(x) in.

$\large{ \begin{cases} f(x) = 2 {x}^{2} - x - 6 \\ g(x) = 4 - x \end{cases}} \\ \large{f(x) + g(x) = (2 {x}^{2} - x - 6) + (4 - x)} \\ \large{f(x) + g(x) = 2 {x}^{2} - x - 6 + 4 - x}$

Évaluate/Combine like terms.

$\large{f(x) + g(x) = 2 {x}^{2} - 2x - 2}$

The function can be factored so there are two answers. (Both of them work as one of them is factored form while the other one is not.)

$\large{(f + g)(x) = 2 {x}^{2} -2x -2}$

Alternative

$\large{(f + g)(x) = 2({x}^{2} -x - 1)}$

Answer

(f+g)(x) = 2x²-2x-2
(f+g)(x) = 2(x²-x-1)

Both answers work. The second answer is in factored form.

Let me know if you have any doubts!

8 0

2 years ago

Can u please help me

Alchen [17]

Answer:

that answer u put is correct and r u in K12 to lol

8 0

3 years ago

As a store manger you would like to find out the average time it takes to unload the truck which delivers the merchandise for yo

Georgia [21]

Answer:

The upper boundary of the 95% confidence interval for the average unload time is 264.97 minutes

Step-by-step explanation:

We have the standard deviation for the sample, but not for the population, so we use the students t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 35 - 1 = 35

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 34 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.9}{2} = 0.975([tex]t_{975}$ ). So we have T = 2.0322