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Alchen [17]
3 years ago
6

What is the volume of this. Pyramid 720 cm2 1080cm2 1440 cm2 2160 cm2

Mathematics
1 answer:
Agata [3.3K]3 years ago
8 0

Answer:

Option (1)

Step-by-step explanation:

To calculate the volume of the given pyramid,

Formula to be used,

Volume = \frac{1}{3}(\text{Area of the triangular base)}(\text{Height})

Area of the triangular base = \frac{1}{2}(\text{Base})(\text{Height})

                                             = \frac{1}{2}(9)(15)

                                             = 67.5 cm²

Now volume of the pyramid = \frac{1}{3}(67.5)(32)

                                               = 720 cm³

Therefore, Option (1) will be the correct option.

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Three numerical expressions that are equivalent to (0.0004) x (0.005)
zzz [600]

Answer:

Numerical expression 1

\frac{4}{10000} * \frac{5}{1000}  = \frac{20}{10000000} = \frac{1}{500000}

Numerical expression 2

\frac{1}{50000} = 0.2 * 10^{-4} = 2 * 10^{-5}

Numerical expression 3

1 : 50000

Step-by-step explanation:

Numerical expression 1

\frac{4}{10000} * \frac{5}{1000}  = \frac{20}{10000000} = \frac{1}{500000}

Numerical expression 2

\frac{1}{50000} = 0.2 * 10^{-4} = 2 * 10^{-5}

Numerical expression 3

1 : 50000

4 0
2 years ago
an 8 by 19 ft wall has three 4 by 5 ft windows.the area of the three windows is what percent of the area of the entire wall (inc
erica [24]

Answer:

39.5% (3 sf)

Step-by-step explanation:

Area of 1 window: 4×5 = 20 ft²

2 windows: 3×20 = 60ft²

Area of the wall: 8×19 = 152 ft³

Percentage of window area:

60/152 × 100 = 39.47368421%

= 39.5% (3 sf)

4 0
2 years ago
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kati45 [8]

ok Step-by-step explanation:

5 0
2 years ago
A short-wave radio antenna is supported by two guy wires, 150 ft and 180 ft long. Each wire is attached to the top of the antenn
Dafna1 [17]

The distance between the anchor points of the two guy wires holding radio antenna is 181 feet (to the nearest foot)

<h3>How to determine the distance between the two anchor points of the guy wire</h3>

The problem will be solved using SOH CAH TOA

let the distance between the 150 ft long guy wire and the radio antenna be x

let the distance between the 180 ft long guy wire and the radio antenna be y

cos 65° = x / 150

x = cos 65° * 150

x = 63.39 ft

The height of the antenna

sin 65° = height of antenna / 150

height of antenna = sin 65 * 150

height of antenna = 135.95

using Pythagoras theorem

(length of guy wire)² = (height of the antenna)² + (anchor distance)²

(anchor distance)² = 180² - 135.95²

anchor distance = √(180² - 135.95²)

anchor distance = 117.97

The anchor points distance apart

= 63.39 + 117.97

= 181 (to the nearest foot)

Learn more on Pythagoras theorem here:

brainly.com/question/29241066

#SPJ1

4 0
1 year ago
The square root of t is greater than 2 and less than 3.5. How many integer values of t satisfy this condition?
Jlenok [28]

2

8 integers

4 0
3 years ago
Read 2 more answers
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