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3 years ago

14

consider the balanced chemical equation below. when the chemical reaction was carried out calculated theoretical was yield for s

odium bromide 162 grams but the measured yield was 150 grams what is the percent yield?

1 answer:

8_murik_8 [283]3 years ago

7 0

Answer:

Explanation:

% yield = (actual yield / theoretical yield) X 100

For this question,

% yield = (150g/ 162 g) X 100 = 92.6%

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Lead metal can be extracted from a mineral called galena, which contains 86.6% lead by mass. a particular ore contains 68.5% gal

rjkz [21]

The volume of sphere can be calculated using the following formula:

$V=\frac{4}{3}\pi r^{3}$

Here, r is radius of the sphere which is 8 cm. Putting the value,

$V=\frac{4}{3}\pi r^{3}=\frac{4}{3}(3.14)(8 cm)^{3}=2143.57 cm^{3}$

This is equal to the volume of lead, density of lead is $11.34 g/cm^{3}$ thus, mass of lead can be calculated as follows:

$m=d\times V=11.34 g/cm^{3}\times 2143.57 cm^{3}=2.43\times 10^{4}g$

Let the mass of ore be 1 g, 68.5% of galena is obtained by mass, thus, mass of galena obtained will be 0.685 g.

Now, 86.6% of lead is obtained from this gram of galena, thus, mass of lead will be:

m=0.685×0.866=0.5932 g

Therefore, 0.5932 g of lead is obtained from 1 g of ore, if the efficiency is 100%.

For 92.5% efficiency, mass of lead obtained will be:

$m=\frac{92.5}{100}\times 0.5932=0.5487 g$

Thus, 1 g of lead obtain from $\frac{1}{0.5487}=1.822$ grams of ore.

Thus, $2.43\times 10^{4} g$ of lead obtain from:

$2.43\times 10^{4}\times 1.822=4.42\times 10^{4}g=44.2 kg$

Therefore, mass of ore required to make lead sphere is 44.2 kg.

4 0

3 years ago

Read 2 more answers

Solution 1 contains 3.5g of sodium chloride in 500 mL of water. Solution 2 contains 7.5g of glucose in 300 mL of water. If the a

meriva

Answer:

Answer is Object 2 (which has a density of 1.9 g/cm³).

Explanation;

When object is floating, the weight of that object is less than the up thrust on it.

When an object fully submerged and floating, then the weight of that object is equal to the up thrust on it.

This is known as the Archemide's principle.

Both up thrust and weight depends on the density. Hence, if the density of the solution is high, then the up thrust also high. If the density high, the the weight of the object also high.

Hence, to sink the object in water, that object should be denser than water. Hence, answer is object 3 which has a higher density than water.

Explanation:

8 0

3 years ago

Give an example of a physical model of the circulatory system

GaryK [48]

Arteries carry blood away from the heart and veins carry blood back to the heart. Hope that helps (:

6 0

3 years ago

what is the mole fraction of neon in a mixture that contains 0.628 g of helium, 11.491 g of neon, and 7.613 g of argon?

VMariaS [17]

Answer:

0.2

Explanation:

Given parameters:

Mass of helium = 0.628g

Mass of neon = 11.491g

Mass of argon = 7.613g

Unknown:

Mole fraction of neon = ?

Solution:

The mole fraction of an element is the number of moles of that element to the total number of moles in the gas mixture.

We need to calculate the number of moles of each element first;

Number of moles = $\frac{mass}{molar mass}$

Molar mass of Helium = 4g/mol

Molar mass of Neon = 20g/mol

Molar mass of Argon = 40g/mol

Number of moles of He = $\frac{0.628}{4}$ = 0.16moles

Number of moles of Ne = $\frac{11.491}{20}$ = 0.58moles

Number of moles of Ar = $\frac{7.613}{40}$ = 0.19moles

Total number of moles = 0.16moles + 0.58moles + 0.19moles = 0.93moles

Mole fraction Neon = $\frac{0.19}{0.93}$ = 0.2

4 0

3 years ago

You discover that the complex decomposes in water. You dissolve 0.1000 g of the complex in H2O and add excess CaHg(SCN)4, which

katovenus [111]

Answer:

<u>0.01320g</u>

Explanation:

All the cobalt in the sample is in the precipitate, so you need to determine the amount of cobalt in the precipitate.

<u>1. Calculate the molar mass of CoHg(SCN)₄</u>

Atom Number of atoms Atomic mass Product

g/mol g/mol

Co 1 58.933 58.933

Hg 1 200.59 200.59

S 4 32.065 128.26

C 4 12.011 48.044

N 4 14.007 56.028

=========

Molar mass: 491.855

<u>2. Set a proportion</u>

58.933g of Co / 491.855 g of compound = x / 0.1102 g of compound

Clear and compute:

x = 0.1102 × 58.933 / 491.855 g of Co

x = 0.01320393 g

Round to four significant figures: 0.01320g of cobalt ← answer

3 0

4 years ago