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2 years ago

Why do girls like boys who act rude more than boys that are actually nice!

Chemistry

2 answers:

Svetach [21]2 years ago

8 0

Answer:

When a guy who shows a girl to much emotion, they get turned off.

Explanation:

77julia77 [94]2 years ago

6 0

Answer:

i dont know werid world out there

Explanation:

girls are confusing

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Atoms of a substance are rearranged _______.

Yanka [14]

Atoms are never rearranged

6 0

3 years ago

If you have a solution that is 15 percent by mass of KCl in benzene, what is the new boiling point?

Serhud [2]

Answer:

https://www.chegg.com/homework-help/questions-and-answers/1-10-points-solution-15-percent-mass-kcl-benzene-new-boiling-point--901-c-b-921-c-c-821-c--q63751186

Explanation: Thats your answer

3 0

2 years ago

Can someone answer 1-10 for me or the one you know I’ll give you brainlest!!!

Reika [66]

1. Coefficient
2. Subscript
3. Products
4. Reactants
5. Balance
6. Combustion
7. Decomposition
8. Single replacement
9. Double replacement
10. Synthesis
I’m sorry if I’m wrong

5 0

3 years ago

Engine size is measured by how much air the cylinders displace. A 1996 Pontiac V8 has an engine size of 316.6 cubic inches. What

inna [77]

The size of this engine in cubic meters is $0.0052 m^{3}$ .

Explanation:

As it is stated that engine size can be measured depending upon the amount of air the cylinders displace, it is also stated that the engine of model Pontiac V8 has a size of 316.6 cubic inches. The problem is to convert the size of engine in cubic meters. We know that 1 inch = 0.0254 m.

Then $1 inch^{3}=(0.0254)^{3} m^{3}$

As here the size of engine is 316.6 cubic inches, then in metres it will be

$316.6 \text { inches }^{3}=316.6 \times(0.0254)^{3} \mathrm{m}^{3}=0.0052 \mathrm{m}^{3}$

Thus, the size of the engine in cubic meters will be $0.0052 m^{3}$ .

3 0

3 years ago

Calculate ∆G ◦ r for the decomposition of mercury(II) oxide 2 HgO(s) → 2 Hg(ℓ) + O2(g) ∆H◦ f −90.83 − − (kJ · mol−1 ) ∆S ◦ m 70.

bagirrra123 [75]

Answer:

4. +117,1 kJ/mol

Explanation:

ΔG of a reaction is:

ΔGr = ΔHr - TΔSr (1)

For the reaction:

2 HgO(s) → 2 Hg(l) + O₂(g)

ΔHr: 2ΔHf Hg(l) + ΔHf O₂(g) - 2ΔHf HgO(s)

As ΔHf of Hg(l) and ΔHf O₂(g) are 0:

ΔHr: - 2ΔHf HgO(s) = 181,66 kJ/mol

In the same way ΔSr is:

ΔSr= 2ΔS° Hg(l) + ΔS° O₂(g) - 2ΔS° HgO(s)

ΔSr= 2* 76,02J/Kmol + 205,14 J/Kmol - 2*70,19 J/Kmol

ΔSr= 216,8 J/Kmol = 0,216 kJ/Kmol

Thus, ΔGr at 298K is:

ΔGr = 181,66 kJ/mol - 298K*0,216kJ/Kmol

ΔGr = +117,3 kJ/mol ≈ 4. +117,1 kJ/mol

I hope it helps!

5 0

3 years ago