Triangle ABC is translated 2 units down and 1 unit left. Then it is rotated 90 degrees clockwise about the origin to create tria
ngle A'B'C'. What are the coordinates of the vertices of triangle A'B'C' ? A.) A'(-2, 0), B'(1, -1), C'(-1, -1) B.)A'(2, 1), B'(5, 0), C'(3, 0) C.) A'(-1, -2), B'(2, -3), C'(0, -3) D.) A'(-2, 1), B'(1, 0), C'(-1, 0)
2 answers:
Answer : D.) A'(-2, 1), B'(1, 0), C'(-1, 0)
As per the given diagram
Point A : (0,0)
Point B: (1,3)
Point C : (1,1)
WE translate each point 2 units down and 1 unit left.
The points are in ordered pair (x,y)
For 2 units down we subtract 2 from y
For 1 unit left we subtract 1 from x
After translation
Point A : (0,0) ---> (0-1 , 0-2) ---> (-1, -2)
Point B: (1,3) ---> (1-1 , 3-2) ---> (0, 1)
Point C : (1,1) ---> (1-1 , 1-2) ---> (0, -1)
Now we rotated 90 degrees clockwise about the origin
While rotating 90 degree clockwise (x , y) becomes (y , -x)
Point A' : (-1, -2) ---> (-2, 1)
Point B': (0, 1) -----> (1,0)
Point C' : (0, -1) -----> (-1 ,0)
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