Answer:
The intercepts of the third degree polynomial corresponds to the zeros of the equation
y = d*(x-a)*(x-b)(x-c)
Where a, b and c are the roots of the polynomial and d an adjustment coefficient.
y = d*(x+2)*(x)*(x-3)
Lets assume d = 1, and we get
y = (x+2)*(x)*(x-3) = x^3 - x^2 - 6x
We graph the equation in the attached file.
1 rad=57.3°
288÷57.3=5.02 rad
7/21 for the first and 9/27 for the second
<h3>
Answer: The solution of the system of equations is (1,7).</h3>
Step-by-step explanation: Given system of equations
y = 5x + 2 and
3x = –y + 10.
Substituting y= 5x+2 in second equation, we get
3x = -(5x+2) +10.
Distributing minus sign in (5x+2), we get
3x= -5x-2+10.
3x = -5x + 8.
Adding 5x on both sides, we get
3x+5x = -5x+5x +8
8x = 8.
Dividing both sides by 8, we get
8x/8 = 8/8
x = 1.
Plugging x=1 in first equation, we get
y = 5(1) +2
y = 5+2=7.
<h3>Therefore, the solution of the system of equations is (1,7).</h3>
Answer:
C-1/64
Step-by-step explanation:
(1/4)(1/4)(1/4)=1/64
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