in a class containing 32 students, a student can either do Government or History or both. If 16 students do Government, 18 do Hi
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To solve this we are going to use the half life equation 
Where:
is the initial sample
is the time in years
is the half life of the substance
is the remainder quantity after years
From the problem we know that:
Lets replace those values in our equation to find:
We can conclude that after 1600 years of radioactive decay, the mass of the 100-gram sample will be 91.7 grams.
Where:
From the problem we know that:
Lets replace those values in our equation to find
We can conclude that after 1600 years of radioactive decay, the mass of the 100-gram sample will be 91.7 grams.
Answer:
= 3n + 4
Step-by-step explanation:
there is a common difference between consecutive terms , that is
10 - 7 = 13 - 10 = 16 - 13 = 3
this indicates the sequence is arithmetic with nth term
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
here a₁ = 7 and d = 3 , then
= 7 + 3(n - 1) = 7 + 3n - 3 = 3n + 4