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kotykmax [81]
3 years ago
5

Can someone plz answer!? problem below

Mathematics
2 answers:
-BARSIC- [3]3 years ago
5 0
Okay, Given that these are vertical angles with each other, we can set them equal to each other. This means our equation to find out what x is, is 

3x-3=2x+13

We now need to move like terms to each other. We can do this by adding 3 to both sides of the equation to cancel our the -3.

Our equation will now look like:
3x=2x+16

Now we will move the 2x over to the opposite side to get the 16 alone. We will need to subtract 2x from both sides.
This will leave us with

x=16. This means that we can now plug 16 in for the x value. 

This means that angle 

3(16)-3= 45 
and
2(16)+13= 45.

This means that the measurement of each angle will be 45 degrees.



MaRussiya [10]3 years ago
4 0

3X-3=2X+13

3X-2X=13+3

X=16

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How does the shape of a cross-section of a 3D figure parallel to the base relate to the volume of the 3D figure?
Ket [755]

Answer:

The shape of each cross-section of a 3D figure,  relates to the volume because the area of the cross-section is determined by its shape and the area of this cross section is in the sum that calculates the volume of this 3D figure.

Step-by-step explanation:

An infinite sum of all the all the cross-sections of a 3D figure parallel to the base equals the volume of that 3D figure.

3 0
3 years ago
Find f(2) and f(a+h) when f(x)=3x^2+2x+4
wolverine [178]
F(2) = 3(2)^2 + 2(2) + 4

= 3(4) + 4 + 4

= 12 + 8

f(2) = 20

f(a+h) = 3(a+h)^2 + 2(a+h) + 4

= 3(a^2 + 2ah + h^2) + 2a + 2h + 4

f(a+h) = 3a^2 + 6ah + 3h^2 + 2a + 2h + 4
4 0
3 years ago
The weights of certain machine components are normally distributed with a mean of 8.04 g and a standard deviation of 0.08 g. Fin
NISA [10]

Answer:

The bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.

Step-by-step explanation:

We are given that

Mean, \mu=8.04 g

Standard deviation, \sigma=0.08g

We have to find the two weights that separate the top 3% and the bottom 3%.

Let x be the weight of  machine components

P(Xx_2)=0.03

P(X

=0.03

From z- table we get

P(Z1.88)=0.03

Therefore, we get

\frac{x_1-8.04}{0.08}=-1.88

x_1-8.04=-1.88\times 0.08

x_1=-1.88\times 0.08+8.04

x_1=7.8896

\frac{x_2-8.04}{0.08}=1.88

x_2=1.88\times 0.08+8.04

x_2=8.1904

Hence, the bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.

5 0
2 years ago
Q2<br>What is 23.3 x 0.463 correct to three decimal places?​
Black_prince [1.1K]

Answer:

10.787

Step-by-step explanation:

Given :

23.3×0.463

After multiplying this equation ,

10.787

Therefore, answer will be 10.787

6 0
2 years ago
1. (a) Use the integral test to show that P[infinity] n=1 1/n4 converges. (b) Find the 10th partial sum, s10, of the series P[in
scZoUnD [109]

Answer:

Step-by-step explanation:

a) \int\limits^{\infty} _1 {\frac{1}{n^4} } \, dn\\ =\frac{n^{-3} }{-3}

Substitute limits to get

= \frac{1}{3}

Thus converges.

b) 10th partial sum =

\int\limits^{10} _1 {\frac{1}{n^4} } \, dn\\ =\frac{n^{-3} }{-3}

=\frac{-1}{3} (0.001-1)\\= 0.333

c) Z [infinity] n+1 1 /x ^4 dx ≤ s − sn ≤ Z [infinity] n 1 /x^ 4 dx, (1)

where s is the sum of P[infinity] n=1 1/n4 and sn is the nth partial sum of P[infinity] n=1 1/n4 .

(question is not clear)

3 0
3 years ago
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