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3 years ago

1Prove that1: sin/1-cot + cos/1-tan=cos+sin

Mathematics

1 answer:

Anit [1.1K]3 years ago

4 0

Answer:

have:

$\frac{sin}{1-cot}+\frac{cos}{1-tan}\\\\=\frac{sin}{1-\frac{cos}{sin} }+\frac{cos}{1-\frac{sin}{cos} }\\\\=\frac{sin^{2} }{sin-cos}+\frac{cos^{2} }{cos-sin} \\\\=\frac{sin^{2} }{sin-cos}-\frac{cos^{2} }{cos-sin}\\\\=\frac{sin^{2}-cos^{2} }{sin - cos}\\\\=\frac{(sin-cos)(sin+cos)}{sin-cos}\\\\=sin+cos$

Step-by-step explanation:

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Which answer is an equation in point-slope form for the given point and slope?

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Answer:

Step-by-step explanation:

Point-slope equation for line of slope m that passes through (x₀,y₀):

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2 years ago

Two streams flow into a reservoir. Let X and Y be two continuous random variables representing the flow of each stream with join

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Answer:

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Step-by-step explanation:

Given:

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where a and b represent -infinity to +infinity (in other words, the bound of the distribution)

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$c\int\limits^3_0 {(\frac{9x}{2} +\frac{27x}{3} ) \, dx = 1$

Add fraction

$c\int\limits^3_0 {(\frac{27x + 54x}{6}) \, dx = 1$

$c\int\limits^3_0 {\frac{81x}{6} \, dx = 1$

Rewrite;

$c\int\limits^3_0 (81x * \frac{1}{6}) \, dx = 1$

The $\frac{1}{6}$ is a constant, so it can be removed from the integral sign to give

$c * \frac{1}{6}\int\limits^3_0 (81x ) \, dx = 1$

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Integrate with respect to x

$\frac{c}{6} * \frac{81x^{2}}{2} (0,3) = 1$

Substitute 0 and 3 for x

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$\frac{c}{6} * \frac{81 * 9 - 0}{2} = 1$

$\frac{c}{6} * \frac{729}{2} = 1$

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Multiply both sides by $\frac{12}{729}$

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3 years ago

15+0.5x=25+0.25x please show how

sveticcg [70]

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

x= 40

8 0

2 years ago

Read 2 more answers

Un terreno de 4200 metros cuadrados de superficie se quiere dividir en dos lotes de manera que el lote menor sea tres cuartas pa

lions [1.4K]

Answer:

El lote menor tendrá 1800 m^2

El lote mayor tendrá 2400 m^2

Step-by-step explanation:

Definamos las variables:

M = superficie del lote mayor

m = superficie del lote menor.

Sabemos que el terreno tiene en total 4200 m^2

Entonces:

M + m = 4200 m^2.

Y queremos que el lote menor sea 3/4 del lote mayor, entonces:

m = (3/4)*M

Podemos reemplazar esto en la ecuación de arriba para obtener:

M + ( (3/4)*M) = 4200 m^2.

Y ahora podemos resolver esto para M

M + (3/4)*M = 4200m^2

M*(1 + 3/4) = 4200m^2

M*(4/4 + 3/4) = 4200 m^2

M*(7/4) = 4200m^2

M = (4/7)*(4200m^2) = 2400m^2

Esto significa que la superficie del mayor lote es 2400 m^2

Y la superficie del menor se puede obtener con la ecuación:

m = (3/4)*M

m = (3/4)*2400m^2 = 1800m^2

La superficie del lote menor es 1800m^2

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3 years ago

15 POINTS 8m+4m+7m-2n what’s the answer

Romashka-Z-Leto [24]

To simplify combine like terms:

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Simplified: 15m + 2n

6 0

3 years ago

Read 2 more answers

1Prove that1: sin/1-cot + cos/1-tan=cos+sin​

1Prove that1: sin/1-cot + cos/1-tan=cos+sin