When a the irregularities of one surface come into contact with those of another surface ,occurs
1 answer:
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Answer:
<em>The range is 15.15 m and the time in the air is 1.01 s</em>
Explanation:
<u>Horizontal Motion</u>
When an object is thrown horizontally (with angle 0°) with a speed v from a height h, it follows a curved path ruled exclusively by gravity until it eventually hits the ground.
The range or maximum horizontal distance traveled by the object can be calculated as follows:
To calculate the time the object takes to hit the ground, we use the equation below:
The cannon is shot from a height of h=5 m with an initial speed of v=15 m/s. The range is calculated below:
d = 15.15 m
The time in the air is:
t = 1.01 s
The range is 15.15 m and the time in the air is 1.01 s
Answer:
a) t = 1.75 s
b) x = 31.5 m
Explanation:
a) The time at which Tom should drop the net can be found using the following equation:
Where:
: is the final height = 0
y₀: is the initial height = 15 m
g: is the gravity = 9.81 m/s²
: is the initial vertical velocity of the net = 0 (it is dropped from rest)
Hence, Tom should drop the net at 1.75 s before Jerry is under the bridge.
b) We can find the distance at which is Jerry when Tom drops the net as follows:
Then, Jerry is at 31.5 meters from the bridge when Jerry drops the net.
I hope it helps you!