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Misha Larkins [42]
3 years ago
6

Write the electric field at point p in component form. assume that x-axis is horizontal and points to the right, and y-axis poin

ts upward.
Physics
1 answer:
salantis [7]3 years ago
5 0
E = q/r^2

where r is perpendicular distance between the point and source charge

Ex = E cos theta

Ey = E sin theta

take theta angle between horizontal and line joining the point charge and the point

 
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An object has a -8 C charge. The object breaks into two pieces. One piece has a charge of -2 C. What is the exact charge (in C)
Varvara68 [4.7K]

As we know the property of charge that charge is always conserved

so we can say

Q = q_1 + q_2

here we know that total charge is

Q = -8 C

and we also know that

q_1 = -2C

from above equation we can say

-8 = -2 + q_2

q_2 = -8 +2 = -6 C

so the other charge will be -6 C

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A bumblebee carries pollen from the male portion of a plant to the female portion of the same flower. Fertilization occurs. Whic
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The force of gravity on an object is known as its mass. Please select the best answer from the choices provided T F
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3 years ago
An electron is released form rest in a region of space where a uniform electric field is present. Joanna claims that its kinetic
Blizzard [7]

Answer:

reviewing the opinion of the two students we see that neither is right, since when the kinetic energy increases the potential energy decreases by the same value

Explanation:

For this exercise we must use the law of conservation of energy.

Starting point. Resting electron

        Em₀ = U = eV

the potential difference and the electric field are related

         V = - E d

Final point. When leaving the electric field

           Em_{f} = K = ½ m v²

           Em₀ = Em_{f}

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From this expression we see that when an electron moves from the initial point to the final point, the potential energy must decrease, for the total energy to be constant.

When reviewing the opinion of the two students we see that neither is right, since when the kinetic energy increases the potential energy decreases by the same value

3 0
4 years ago
A medicine ball has a mass of 6 kg and is thrown with a speed of 4 m/s. What is its kinetic energy?
zhenek [66]

Answer:

\boxed{\sf Kinetic \ energy \ (KE) = 48 \ J}

Given:

Mass (m) = 6 kg

Speed (v) = 4 m/s

To Find:

Kinetic energy (KE)

Explanation:

Formula:

\boxed{ \bold{\sf KE =  \frac{1}{2} m {v}^{2} }}

Substituting values of m & v in the equation:

\sf \implies KE =  \frac{1}{2}  \times 6 \times  {4}^{2}

\sf \implies KE = \frac{1}{ \cancel{2}}  \times  \cancel{2} \times 3 \times 16

\sf \implies KE =3 \times 16

\sf \implies KE = 48 \: J

6 0
4 years ago
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