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olganol [36]
3 years ago
11

If a 1.50 kg mass revolves at the end of a string 0.50 m long, and its tangential speed is 6.0 m/s, calculate the centripetal fo

rce.
Physics
2 answers:
Allisa [31]3 years ago
8 0

Answer:

108\ N

Explanation:

Mass of object, m=1.50\ kg.

Length of string, r=0.50\ m.

Tangential speed, v_t=6.0\ m/s.

Now, centripetal force F of a object moving in given radius r and mass m moving with velocity v.

Here , object moves along the ends of string. Therefore, radius is equal to length of string.

F=\dfrac{m \times v_t^2}{r}.

Putting values of m,v and r in above equation.

We get, F=\dfrac{1.50\times (6.0)^2}{0.50} \ N=108 \ N.

Hence, this is the required solution.

rosijanka [135]3 years ago
5 0
You should get about 110 for an answer
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Two concentric current loops lie in the same plane. The smaller loop has a radius of 3.8 cm and a current of 12 A . The bigger l
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R_2=6.33cm

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\frac{\mu_0I_2}{2R_2}=\frac{\mu_0I_1}{2R_1}

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R_2=\frac{I_2}{I_1}R_1

Which for our values means:

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Ideal gases are often studied at standard ambient temperature and pressure (satp). The international union of pure and applied c
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In science, we can start studying gases with the concept of ideal gas, as they do not collide one to another and are assumed to be perfect spheres with no relevant interactions.

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Learn more about ideal gases: brainly.com/question/26450101

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