If a 1.50 kg mass revolves at the end of a string 0.50 m long, and its tangential speed is 6.0 m/s, calculate the centripetal fo
2 answers:
Answer:
Explanation:
Mass of object,
Length of string,
Tangential speed,
Now, centripetal force F of a object moving in given radius r and mass m moving with velocity v.
Here , object moves along the ends of string. Therefore, radius is equal to length of string.
Putting values of m,v and r in above equation.
We get,
Hence, this is the required solution.
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Answer:
T = 17649.03 N = 17.65 KN
Explanation:
The tension in the cable must be equal to the apparent weight of the passenger. For upward acceleration:
where,
T = Tension in cable = ?
= Apparent weight
m = mass = 1603 kg
g = acceleration due to gravity = 9.81 m/s²
a = acceleration of elevator = 1.2 m/s²
Therefore,
<u>T = 17649.03 N = 17.65 KN</u>
data which is expressed in form of following way
here in above expression
= true value
= uncertainty in the value
now the relative uncertainty is given as
now by above formula we can say
a) 2.70 ± 0.05cm
here
True value = 2.70
uncertainty = 0.05
Relative uncertainty = = 0.0185
b) 12.02 ± 0.08cm
here
True value = 12.02
uncertainty = 0.08
Relative uncertainty = = 0.00665