1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
olganol [36]
3 years ago
11

If a 1.50 kg mass revolves at the end of a string 0.50 m long, and its tangential speed is 6.0 m/s, calculate the centripetal fo

rce.
Physics
2 answers:
Allisa [31]3 years ago
8 0

Answer:

108\ N

Explanation:

Mass of object, m=1.50\ kg.

Length of string, r=0.50\ m.

Tangential speed, v_t=6.0\ m/s.

Now, centripetal force F of a object moving in given radius r and mass m moving with velocity v.

Here , object moves along the ends of string. Therefore, radius is equal to length of string.

F=\dfrac{m \times v_t^2}{r}.

Putting values of m,v and r in above equation.

We get, F=\dfrac{1.50\times (6.0)^2}{0.50} \ N=108 \ N.

Hence, this is the required solution.

rosijanka [135]3 years ago
5 0
You should get about 110 for an answer
You might be interested in
ფიზიკაში მჭირდება დახმარება ნაგლმა მასწავლებელმა მთელი თვე გააცდინა და როცა დაბრუნდა ეგრევე საკონტროლო ისეთი საკითხებით რომელიც
MakcuM [25]

Answer:

The photo is blocked cant see anything

Explanation:

3 0
3 years ago
If a device uses 280 watts of power a day, about how many kilowatt-hours will it use in 30 days?
Novay_Z [31]

Answer:C

Explanation:

Power=280watts=280/1000 kilowatts

Power=0.28 kilowatts

Device use 0.28 kilowatts in 1 day

1day=24hours

Device use 0.28 kilowatts in 24hours

30days=30 x 24=720 hours

For 720 hours=(0.28x720) ➗ 24

For 720 hours=201.6 ➗ 24

For 720 hours=8.4

6 0
3 years ago
A hockey puck has a coefficient of kinetic friction of μk = .35. If the puck feels a normal force (FN) of 5 N, what is the frict
alina1380 [7]

Answer:

The frictional force is  F_f =  1.75 \  N

Explanation:

From the question we are told that

     The coefficient of kinetic force is  μk = 0.35

     The normal force felt by the puck is  F_N  =  5 \  N

Generally the frictional force that acts on the puck is mathematically represented as

          F_f =  \mu_k  *  F_N

=>       F_f =  0.35  *  5

=>       F_f =  1.75 \  N

3 0
3 years ago
Determine the density of a rectangular piece of concrete that measures 3.7 cm by 2.1 cm by 5.8 cm and has a mass of 43.8 grams.
Novay_Z [31]
It is customary to work in SI units.

Calculate the volume of the concrete.
V = 3.7*2.1*5.8 cm³ = 45.066 cm³ = 45.066 x 10 ⁻⁶ m³

The mass is  43.8 g = 43.8 x 10⁻³ kg

The density is mass/volume.
Density = (43.8 x 10⁻³ kg)/(45.066 x 10⁻⁶ m³) = 971.9 kg/m³

Answer: 971.9 kg/m³
5 0
3 years ago
A ball is thrown toward a cliff of height h with a speed of 33 m/s and an angle of 60∘ above horizontal. It lands on the edge of
Veseljchak [2.6K]

Answer:

(a). The height of the cliff is 41.67 m.

(b). The maximum height of the ball is 41.67 m

(c). The ball's impact speed is 16.52 m/s.

Explanation:

Given that,

Speed = 33 m/s

Angle = 60°

Time = 3.0 sec

(a). We need to calculate the height of the cliff

Using equation of motion

h=ut-\dfrac{1}{2}gt^2

h=(u\sin60)\times t-\dfrac{1}{2}gt^2

Put the value into the formula

h=33\times\sin60\times3.0-\dfrac{1}{2}\times9.8\times(3.0)^2

h=41.6\ m

(b). We need to calculate the maximum height of the ball

Using formula of height

h_{max}=\dfrac{(u\sin\theta)^2}{2g}

Put the value into the formula

h=\dfrac{(33\sin60)^2}{2\times 9.8}

h=41.67\ m

(c). We need to calculate the vertical component of velocity of ball

Using equation of motion

v=u-gt

v=u\sin\theta-gt

Put the value into the formula

v_{y}=33\times\sin 60-9.8\times3.0

v_{y}=-0.82\ m/s

We need to calculate the horizontal component of velocity of ball

Using formula of velocity

v_{x}=u\cos\theta

Put the value into the formula

v_{x}=33\times\cos60

v_{x}=16.5\ m/s

We need to calculate the ball's impact speed

Using formula of velocity

v=\sqrt{v_{x}^2+v_{y}^2}

Put the value into the formula

v=\sqrt{(16.5)^2+(-0.82)^2}

v=16.52\ m/s

Hence, (a). The height of the cliff is 41.67 m.

(b). The maximum height of the ball is 41.67 m

(c). The ball's impact speed is 16.52 m/s.

3 0
3 years ago
Other questions:
  • Which statement correctly relates science and its influence on society? Science can neither solve societal problems nor influenc
    14·2 answers
  • Which is a characteristic property of acids? a. They turn blue litmus paper red. b. They turn red litmus paper blue. c. They tas
    10·1 answer
  • Problem
    6·1 answer
  • In what form does carbon return to the atmosphere after it is released from the burning of fossil fuels
    6·1 answer
  • 2. Why is an experiment called a controlled study?
    5·2 answers
  • Que es entrenamientos físicos?
    9·1 answer
  • Hurry pls I need help
    8·1 answer
  • Why does it take more force to get a resting object to move than it does to keep
    6·1 answer
  • If you get scared when swimming,panicking just makes you breathe faster and uses up more precious energy.
    15·1 answer
  • After travelling 4.0 km, the train reaches its maximum speed. it continues at this constant speed on the next section of the tra
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!