Answer:
0.015 atm
Explanation:
The pressure of the gas can be calculated using Ideal Gas Law:
<u>Where:</u>
n: is the number of moles of the gas
R: is the gas constant = 0.082 L*atm/(K*mol)
V: is the volume of the container = 1.64 L
T: is the temperature
We need to find the number of moles and the temperature. The number of moles is:
<u>Where:</u>
M: is the molar mass of the N₂ = 14.007 g/mol*2 = 28.014 g/mol
m: is the mass of the gas = 0.226 g
Now, the temperature can be found using the following equation:
<u>Where:</u>
R: is the gas constant = 0.082 L*atm/K*mol = 8.314 J/K*mol
: is the root-mean-square speed of the gas = 182 m/s
By solving the above equation for T, we have:
Finally, we can find the pressure of the gas:
Therefore, the pressure of the gas is 0.015 atm.
I hope it helps you!
A. an accelerating charged charged particle or changing magnetic fields
Answer:
102900 Joules
Explanation:
Assuming the kinetic energy was zero at the moment of release, you can make the following argument to solve the problem:
The potential energy at full height was mgh. We are told that after 70% of the distance, i.e., mg(0.3h) = 44.1kJ. Since potential energy is linear in altitude h, we get get the full potential energy to be 44.1kJ/0.3. The difference between full potential energy and the one after 70% of the way must equal the gained kinetic energy (neglecting stuff like heat due to friction). So,
44.1kJ/0.3 - 44.1kJ = 0.7*44.1kJ/0.3 = 102.9kJ = Ekinetic
The kinetic energy after 70% of the falling distance was 102.9 kJ.
Answer:
E. All of the answers are correct
Explanation:
Overload principle in fitness training is associated with a gradual development of an athlete's abilities by progressively increasing the athlete's load and training.
In order to do this, the athlete's limit must be surpassed albeit gradually at first then picked up later over time.
Answer:
Induced emf in the loop is 0.02208 volt.
Induced current in the loop is 0.0368 A.
Explanation:
Given that,
Area of the single loop,
The initial value of uniform magnetic field, B = 3.8 T
The magnetic field is decreasing at a constant rate,
(a) The induced emf in the loop is given by the rate of change of magnetic flux.
(b) Resistance of the loop is 0.6 ohms. Let I is the current induced in the loop. Using Ohm's law :
Hence, this is the required solution.