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Natali5045456 [20]
3 years ago
15

Question 7 (1 point)

Physics
1 answer:
ioda3 years ago
7 0

Answer:

1150 secs

distance = speed x time

time = distance / speed

230,000 / 200 = 1150

time = 1150 seconds

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in which place does subduction occur? a. at transform boundaries b. where two plates move apart c. at most normal faults d. wher
Evgesh-ka [11]

Answer;

D. where two plates collide

Explanation;

-Subduction zones are plate tectonic boundaries where two plates converge, and one plate is thrust beneath the other. This process results in geohazards, such as earthquakes and volcanoes.

-Subduction zone volcanism occurs where two plates are converging on one another. One plate containing oceanic lithosphere descends beneath the adjacent plate, thus consuming the oceanic lithosphere into the earth's mantle. This on-going process is called subduction.

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Is Mars a gas planet or a rocky planet?
OLEGan [10]
Mars is a rocky planet
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3 years ago
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With what speed must m1 rotate in a circle of radius r if m2 is to remain hanging at rest?
11Alexandr11 [23.1K]
Velocity =2 pie*r/t
distance = 2 (pie) r
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5 0
3 years ago
Two blocks of ice , one four times as heavy as the other, aren at rest on a frozen lake. a person pushes each block the same dis
LenKa [72]

Answer:

The correct answer is B: the kinetic energy of the heavier block is equal to the kinetic energy of the lighter block.

Explanation:

Hi there!

The work done on each block is calculated as follows:

W = F · d

Since the two blocks were pushed the same distance with the same force, the work done on each object is the same.

Using the work-energy theorem, we know that the work done on an object is equal to its change in kinetic energy (KE):

W = ΔKE

W = final KE - initial KE

Since the objects are at rest, initial KE = 0, then:

W = final KE

Since the work done on each block is the same, so will be its final kinetic energy.

The correct answer is B: the kinetic energy of the heavier block is equal to the kinetic energy of the lighter block.

8 0
3 years ago
Calculate a. The heat that must be supplied to a 500.0 g copper kettle containing 400.0 g of water to raise its temperature from
uysha [10]

Explanation:

<h2>For Copper</h2>

dH copper = mCdT copper

<em>(Specific Heat of copper=0.385 J/g C )   </em>

dH = 500 g (0.385 J/g C) (78 C rise)

dH = 15,015 Joules

<h2> For Water</h2>

dH water =  m C dT water

<em>(Specific Heat of copper=</em>4.184 J/g-C<em>)   </em>

<em />

dH = 400 g (4.184 J/g-C) (78 C rise)

dH = 130,540 Joules

total heat = 15,015 + 130,540 = 145,555 Joules

<h2>Percentage for Water  </h2>

(130,540 Joules  / 145,555 Joules) x 100 = 89.7 %

If we consider that we have 3 Significant Figures,

then, the answers become ,

15.0 KJ must be added for Copper

130.5 KJ must be added for Water

and the total of 145 KJ must be added in the kettle with the water

89.7 %  of heat goes to the Water

7 0
3 years ago
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