Answer:
<em>The divers pull in their limbs and curl up their bodies because</em> doing so decreases their moment of inertia and increases their angular velocity
Explanation:
<em>The conservation of angular momentum</em> states that in a rotational system, the initial angular momentum is equal to the final angular momentum if no torque acts on it.
Angular momentum is equal to the product of the moment of inertia about its axis and the angular velocity
Angular momentum = Iω
where I = moment of inertial = mass x
I = m
angular momentum = mω
since angular momentum is constant, one can see that decreasing the radius of rotation about the body by curling in the limb will cause the moment of inertia to decrease and the angular velocity to increase.
NB: mass of the body is constant.
Answer:
wait 1 2 3 and then i jump and gravity falls
Explanation:
Answer:
Explanation:
The electric force between two point charges can be calculated by Coulomb's Law:
We have to calculate the distance between two points; (0,0) and (0.3 m, 0.2 m).
Now we can apply Coulomb's Law
The minus sign in front of the force means that the force is attractive.
The direction of the force can be calculated as follows:
where θ is the angle between F and the x-axis. This angle can be calculated by the triangle with edges 0.3 m, 0.2 m, and 0.36 m.
So, sin(θ) = 0.2/0.36 = 0.55 and cos(θ) = 0.3/0.36 = 0.83.
Finally,
Answer:
option B and C
Explanation:
Control rod are used to regulate the nuclear reactor.
When you insert control rod in the reactor it slows down the nuclear fission inside the reactor and the energy produced in the reactor will be less.
When you remove control road from the reactor the nuclear fission increase inside the reactor and the energy production is high.
Control rod consist of boron, boron absorb the neutron which help to control the nuclear fission.
Hence, the correct answer is option B and C
Answer:
a) u = 6 m/s
b) a = 4 m/s²
c) d(3) = 16 m
Explanation:
equation for the first second
distance will be the average velocity times the time of travel
8 = ½(u + (u + at))t t is one second, so reduces to
8 = u + ½a
velocity at the end of the first second is
v = u + at = u + a
position equation for the second period is
12 = ½((u + a) + (u + a + at))t t is one second so reduces to
12 = u + 3a/2
subtracting the first position equation from the second
12 - 8 = u + 3a/2 - (u + ½a)
a = 4 m/s²
8 = u + ½4
u = 6 m/s
in the third second
d = 6(3) + ½(4)(3²) - 8 - 12
d = 16 m