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il63 [147K]
3 years ago
5

The following appeared in the magazine Financial Times, March 23,1995: "When Elvis Presley died in 1977, there were 48 professio

nal Elvis impersonators. Today there are an estimated 7328. If that growth is projected, by the year 2016 one person in four on the face of the globe will be an Elvis impersonator." This is an example of______________.
Mathematics
1 answer:
IgorLugansk [536]3 years ago
6 0

Answer:

This is an example of Extrapolation

Step-by-step explanation:

Extrapolation is the forecasting of the future based on assumption that present or past trends will continue.

It also assumes the method used for estimating past trends will still be used in future.

For example forecasts of world population.

In this instance, there were 48 impersonators of Elvis Presley, presently it has increased to to 7,328. Estimating that in 2016 based on the present trend, that one of four people will be an Elvis Presley impersonator, is also an example Extrapolation.

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An internal study by the Technology Services department at Lahey Electronics revealed company employees receive an average of 4.
Leno4ka [110]

Answer:

P(4 non-work-related e-mails)=0.1933

P(7 or more non-work-related e-mails)=0.1442

P(3 or less non-work-related e-mails)=0.3771

Step-by-step explanation:

A Poisson distribution is useful to measure the probability of a number of events in a given period, in this problem, receiving a non-work-related e-mail would be the event and an hour would be the period of time.

Its probability mass function is f(k; \lambda) = P(x=k) = \frac{\lambda^k e^{-\lambda}}{k!}, being k the number of events and  λ how many sucesses (events) are per period of time (4.3 in this case)

First, we calculate what is the probability of receiving exactly 4 e-mails:

f(k; \lambda) =P(k=4) =\frac{4.3^4 e^{-\4.3}}{4!}=0.1933

As k is a discrete variable, to know the joint probability of different number of events we add the probability of each value.

The probability of receiving 7 or more is the sum of P(7), P(8), ..., P(∞):

P(k\geq 7 ) =\sum_{i=7}^{\infty}\frac{4.3^i e^{-\4.3}}{i!}=0.1442

Last, the probability of receiving 3 or less is the sum of P(0), P(1), P(2) and P(3):

P(k\leq3 ) =\sum_{i=0}^{3}\frac{4.3^i e^{-\4.3}}{i!}=0.3771

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Answer:

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