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il63 [147K]
3 years ago
5

The following appeared in the magazine Financial Times, March 23,1995: "When Elvis Presley died in 1977, there were 48 professio

nal Elvis impersonators. Today there are an estimated 7328. If that growth is projected, by the year 2016 one person in four on the face of the globe will be an Elvis impersonator." This is an example of______________.
Mathematics
1 answer:
IgorLugansk [536]3 years ago
6 0

Answer:

This is an example of Extrapolation

Step-by-step explanation:

Extrapolation is the forecasting of the future based on assumption that present or past trends will continue.

It also assumes the method used for estimating past trends will still be used in future.

For example forecasts of world population.

In this instance, there were 48 impersonators of Elvis Presley, presently it has increased to to 7,328. Estimating that in 2016 based on the present trend, that one of four people will be an Elvis Presley impersonator, is also an example Extrapolation.

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Rich measured the height of a desk to be 80.7 cm. The actual height of the desk is 80 cm. What is Rich's percent error in this c
Hitman42 [59]

Answer:

0.9%

Step-by-step explanation:

We have been given that Rich measured the height of a desk to be 80.7 cm. The actual height of the desk is 80 cm.

We will use percentage error formula to solve our given problem.

\text{Percentage error}=\frac{\text{Experimental value-Actual value }}{\text{Actual actual}}\times 100

\text{Percentage error}=\frac{80.7-80}{80}\times 100

\text{Percentage error}=\frac{0.7}{80}\times 100

\text{Percentage error}=0.00875\times 100

\text{Percentage error}=0.875\approx 0.9

Therefore, Rich's percent error in calculation is 0.9%.

5 0
3 years ago
Please answer the side questions and the "#justkeepswimming" thank you if you do!!
fenix001 [56]
#just keep swimming I don’t know what you mean
4 0
3 years ago
D<br> Evaluate<br> arcsin<br> (6)]<br> at x = 4.<br> dx
sineoko [7]

Answer:

\frac{1}{2\sqrt{5} }

Step-by-step explanation:

Let, \text{sin}^{-1}(\frac{x}{6}) = y

sin(y) = \frac{x}{6}

\frac{d}{dx}\text{sin(y)}=\frac{d}{dx}(\frac{x}{6})

\frac{d}{dx}\text{sin(y)}=\frac{1}{6}

\frac{d}{dx}\text{sin(y)}=\text{cos}(y)\frac{dy}{dx} ---------(1)

\frac{1}{6}=\text{cos}(y)\frac{dy}{dx}

\frac{dy}{dx}=\frac{1}{6\text{cos(y)}}

cos(y) = \sqrt{1-\text{sin}^{2}(y) }

          = \sqrt{1-(\frac{x}{6})^2}

          = \sqrt{1-(\frac{x^2}{36})}

Therefore, from equation (1),

\frac{dy}{dx}=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}

Or \frac{d}{dx}[\text{sin}^{-1}(\frac{x}{6})]=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}

At x = 4,

\frac{d}{dx}[\text{sin}^{-1}(\frac{4}{6})]=\frac{1}{6\sqrt{1-\frac{4^2}{36}}}

\frac{d}{dx}[\text{sin}^{-1}(\frac{2}{3})]=\frac{1}{6\sqrt{1-\frac{16}{36}}}

                   =\frac{1}{6\sqrt{\frac{36-16}{36}}}

                   =\frac{1}{6\sqrt{\frac{20}{36} }}

                   =\frac{1}{\sqrt{20}}

                   =\frac{1}{2\sqrt{5}}

4 0
2 years ago
Write the equation of the circle with center (5, 1) and radius r = 10
kherson [118]
The standard equation for the circle is:

(x-h)^2+(y-k)^2=r^2, where (h,k) is the center of the circle and r is the radius.

We are given that the center is (5,1) and r=10 so

(x-5)^2+(y-1)^2=100
4 0
3 years ago
Please help ! 1 &amp; 2 :) ​
Korolek [52]

Answer:

first one 401.76, second one 93.96

Step-by-step explanation:

7 0
3 years ago
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