Answer:
The value of the test statistic ![z = -0.6606](https://tex.z-dn.net/?f=z%20%3D%20-0.6606)
Step-by-step explanation:
From the question we are told that
The high dropout rate is
% ![= 0.061](https://tex.z-dn.net/?f=%3D%200.061)
The sample size is ![n = 1000](https://tex.z-dn.net/?f=n%20%3D%201000)
The number of dropouts ![x = 56](https://tex.z-dn.net/?f=x%20%3D%2056)
The probability of having a dropout in 1000 people ![\= x = \frac{56}{1000} = 0.056](https://tex.z-dn.net/?f=%5C%3D%20x%20%20%3D%20%5Cfrac%7B56%7D%7B1000%7D%20%20%3D%20%200.056)
Now setting up Test Hypothesis
Null ![H_o : p = 0.061](https://tex.z-dn.net/?f=H_o%20%3A%20%20p%20%3D%200.061)
Alternative
The Test statistics is mathematically represented as
![z = \frac{\= x - p}{\sqrt{\frac{p(1 -p)}{n} } }](https://tex.z-dn.net/?f=z%20%3D%20%5Cfrac%7B%5C%3D%20x%20-%20p%7D%7B%5Csqrt%7B%5Cfrac%7Bp%281%20-p%29%7D%7Bn%7D%20%7D%20%7D)
substituting values
![z = \frac{0.056 - 0.061}{\sqrt{\frac{0.061(1 -0.061)}{1000} } }](https://tex.z-dn.net/?f=z%20%3D%20%5Cfrac%7B0.056%20-%200.061%7D%7B%5Csqrt%7B%5Cfrac%7B0.061%281%20-0.061%29%7D%7B1000%7D%20%7D%20%7D)
![z = -0.6606](https://tex.z-dn.net/?f=z%20%3D%20-0.6606)
Kylie's first month collection, a1= $ 145
Second month collection , a2= $145+ 20
Third month collection, a3 = $145 +2*20
.
.
.
.
so for n months collection = an-1+20
We get an= 20 + an-1 and a1=145
Answer:
$13.95
Step-by-step explanation:
A)-28
B)-48
C)45
Hope this helps :)
Not really sure but hope this helps