Answer:1/3 divided by 6 equals 18
Step-by-step explanation: If you have a cloth that is 1/3 long then divide it by 6 it would look like 1/3 divided by 1/6 which would then equal 1/18.
Answer:
Step-by-step explanation:
2(2x +4) - 2x = x + 18
4x +8 -2x = x +18
2x -x = 18-8
X = 10
Put the value of x in both side
Left side *+*+*+*+*+
2 ( 2*10+4)-2*10
48-20 = 28
Right side +*+*+*+*+*
X + 18
10+ 18 = 28
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Answer:
0.3
Step-by-step explanation
The formula to find density is m/v=p
m=mass
v=volume
p=density
<h3>---------------------------</h3>
All we have to do is plug in 6g and 20cm^3
This will give us 6/20 which simplifies to 3/10
With this you can easily figure out that the decimal for 3/10 is 0.3
So the density of the ice is <u>0.3</u>
<u>Hope this helped!</u>
Answer:5 by 8 by 5 by 8
Step-by-step explanation: the perimeter is 26 and one side if 5 so you know that another side is also 5. So add 5 and 5 together you get 10. Then subtract 10 from the perimeter(witch we know is 26) and you end up with 16. we know that the last two side lengths are the same so divide 16 by two and the sidle length is 8.
Answer:
0.347% of the total tires will be rejected as underweight.
Step-by-step explanation:
For a standard normal distribution, (with mean 0 and standard deviation 1), the lower and upper quartiles are located at -0.67448 and +0.67448 respectively. Thus the interquartile range (IQR) is 1.34896.
And the manager decides to reject a tire as underweight if it falls more than 1.5 interquartile ranges below the lower quartile of the specified shipment of tires.
1.5 of the Interquartile range = 1.5 × 1.34896 = 2.02344
1.5 of the interquartile range below the lower quartile = (lower quartile) - (1.5 of Interquartile range) = -0.67448 - 2.02344 = -2.69792
The proportion of tires that will fall 1.5 of the interquartile range below the lower quartile = P(x < -2.69792) ≈ P(x < -2.70)
Using data from the normal distribution table
P(x < -2.70) = 0.00347 = 0.347% of the total tires will be rejected as underweight
Hope this Helps!!!
