OK. So they sold 200 raffle tickets, and Jennie bought 5 of them.
What has to happen now in order for Jennie to win both prizes ?
-- First drawing. Jennie wins.
Probability = (5 tickets) / (200 possible draws) = 5/200
Now there are 199 tickets left in the barrel, and Jennie has 4 .
-- Second drawing. Jennie wins.
Probability = (4 tickets) / (199 possible draws) = 4/199 .
The probability of it happening just this way is
(5/200) x (4/199)
= (5 x 4) / (200 x 199)
= 20 / 39,800
= 2 / 3,980 = 1 / 1,990
= 0.0005025... = 0.05 % (rounded)
I think the answer to that is B
I think 6:8:0 is a possible answer for the first question, Math isn’t my greatest subject
Answer:
No
Step-by-step explanation:
Given:
Volume of cone = 144 in³
Diameter of 12 inch
Find:
Volume of cylinder[Same height and radius] is 144 in³ or not
Computation:
Volume of cone = [1/3][π][r²][h]
144 = [1/3][3.14][(12/2)²][h]
144 = 37.68 h
Height of cone = 3.82
Volume of cylinder[Same height and radius] = [π][r²][h]
Volume of cylinder[Same height and radius] = [3.14][6²][3.82]
Volume of cylinder[Same height and radius] = 431.81
Volume of cylinder[Same height and radius] = 432 in³
So,
Volume of cylinder[Same height and radius] is not 144 in³
The scale factor is 1/3 because 9 x 1/3 = 3 and 6 x 1/3 = 2.