The length of ladder is 30 ft.
<h3>How can the feet that made up the side of the building is the top of the ladder be known ?</h3>
The formula below can be used in solving the problem
Tan (∅)= 
∅=70°
opposite = BC
Adjacent = 12 ft
70°= opposite/ 12
opposite= 32.96 ft
Therefore, The length of ladder is 30 ft.
NOTE; Since the actual diagram can not be found i solved another on on the same topic
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CHECK COMPLETE QUESTION BELOW:
Consider the diagram shown where a ladder is leaning against the side of a building. the base of the ladder is 12ft from the building. how long is the ladder? (to the nearest ft)
a. 25ft
b. 30ft
c. 35ft
d. 40ft
D. All real numbers between 111 and 166.5 inclusive.
Answer:
$2.83
Step-by-step explanation:
Diameter of the pool = 24ft
Cost of 1 ft² = $0.15
Area of the pool=?
But the pool is a circular pool,
Area of a circle = Πr² or πd²/4
π = 3.142
Area of the pool = (π * 24) / 4
Area = (3.142 * 24) / 4
Area = 18.85ft²
If 1ft² = $0.15
18.85 = $x
x = (18.85 * 0.15) / 1
x = $2.8275 = $2.83
The cost of the pool is $2.83
Answer:
a) 96m
b) 2 m/s^2
Step-by-step explanation:
The distance travelled in a velocity time graph as shown in the image is the area of the shape. As such, considering the first 14 seconds, the distance covered will be computed by finding the area of the shape.
Note that the shape to be considered ends t the 14 seconds mark. This shape is a trapezium. The area of a trapezium is given as
A = 1/2(a + b) h
where a and b are the parallel sides of the trapezium and h is the height As such, the distance covered in the first 14 seconds
= 1/2 (14 + 10) * 8
= 4 * 24
= 96m
The acceleration after 4 seconds
Acceleration is the rate of change of velocity with time, at time 0 second, the velocity is also 0 but at time 4 seconds, the velocity is 8 m/s hence, the acceleration after 4 seconds
= 8/4
= 2 m/s^2
