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vagabundo [1.1K]
3 years ago
15

I don’t know how to solve this help me please

Mathematics
1 answer:
uysha [10]3 years ago
6 0
I think your answer is that

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During the two hours of the morning rush from 8 a.m. to 10 a.m., 100 customers per hour arrive at the coffee shop. The coffee sh
Anastaziya [24]

So, 40 Customers are waiting at 10 A.M.

According to statement

Number of customers arrives at coffee shop per hour = 100

Capacity of shop for per minute per customer = 0.8 minute

Capacity of shop for customers per hour = 80

Find number of customers are by

Queue growth rate = Demand - Capacity

Put the values in the formula and find the growth rate

So,

Queue growth rate= 100 - 80 = 20.

Length of queue at 10 a.m. = 2 × 20 = 40.

So, 40 Customers are waiting at 10 A.M.

Learn more about GROWTH RATE here brainly.com/question/1437549

#SPJ4

7 0
2 years ago
Can someone do this for me or help me
Elden [556K]
JM=12
JL= 14
MN=?
MK=?

VT= 11
UV= 9
RS=?
ST=?

GF=23
HF=20
GH=?
GE=?

M<1=?
M<2=?
M<3=?
M<4=?
M<5=?
M<6=?
M<7=?
M<8 = 90 degrees

WXZ = 34 degrees
WVZ=90 degrees
ZYW= 56 degrees

These are the only answers I knew, I’m sorry I couldn’t find the rest. If I do find more answers, I’ll comment them.

5 0
3 years ago
I need help on how to solve the problem and the correct answer :)
lakkis [162]

This is a system of linear equations. First, you can add the two equations together to eliminate the y so that you can solve for x:

-5x + -7x = 0 + -96

-12x = -96

x = 8

Use x to solve for y:

-5 * 8 + 8y = 0

Add 40 to both sides and divide by 8:

y = 5

So, x = 8 and y = 5.

3 0
3 years ago
Use a t-distribution to answer this question. Assume the samples are random samples from distributions that are reasonably norma
Nataliya [291]

Answer:

The degrees of freedom is 11.

The proportion in a t-distribution less than -1.4 is 0.095.

Step-by-step explanation:

The complete question is:

Use a t-distribution to answer this question. Assume the samples are random samples from distributions that are reasonably normally distributed, and that a t-statistic will be used for inference about the difference in sample means. State the degrees of freedom used. Find the proportion in a t-distribution less than -1.4  if the samples have sizes 1 = 12 and n 2 = 12 . Enter the exact answer for the degrees of freedom and round your answer for the area to three decimal places. degrees of freedom = Enter your answer; degrees of freedom proportion = Enter your answer; proportion

Solution:

The information provided is:

n_{1}=n_{2}=12\\t-stat=-1.4

Compute the degrees of freedom as follows:

\text{df}=\text{Min}.(n_{1}-1,\ n_{2}-1)

   =\text{Min}.(12-1,\ 12-1)\\\\=\text{Min}.(11,\ 11)\\\\=11

Thus, the degrees of freedom is 11.

Compute the proportion in a t-distribution less than -1.4 as follows:

P(t_{df}

                      =P(t_{11}>1.4)\\\\=0.095

*Use a <em>t</em>-table.

Thus, the proportion in a t-distribution less than -1.4 is 0.095.

8 0
3 years ago
Please help me! I will give you Brainlist if you get it right!​
tatuchka [14]

Answer:

B

Step-by-step explanation:

Find the area of the circle with r = 36/2     Area1 =  π r²

divide Area1 by two since the upper part of the figure is a semi-circle

then finally add and area of the rectangle   Area2 = (18)(36)

Total area = Area 1 + Area 2

5 0
2 years ago
Read 2 more answers
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